anonymous
  • anonymous
3x^2=2x=2x+7
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
too many equal signs
misty1212
  • misty1212
HI!!
misty1212
  • misty1212
is it \[3x^2-2x=2x+7\]?

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More answers

anonymous
  • anonymous
3x2 - 2x = 2x + 7 ⇒ x=2.333 , x=-1 am I right
anonymous
  • anonymous
no
anonymous
  • anonymous
wat did I do wrong
anonymous
  • anonymous
\[\frac{7}{3}\neq 2.333\]
anonymous
  • anonymous
@misty1212 the problem is 3x^2-2x=2x+7
misty1212
  • misty1212
subtract \(2x+7\) from both sides to set it equal to zero, and solve\[3x^2-4x-7=0\] by factoring
misty1212
  • misty1212
i am bad at factoring, but i think it factors as \[(3x-7)(x+1)=0\]
misty1212
  • misty1212
as a matter of fact, i am sure it does
anonymous
  • anonymous
yes the answers are right because my teacher gives us the answers but we have to show the work and she doesn't really teach us so i never know who to do the homework
misty1212
  • misty1212
are you asking how to factor it?
wolf1728
  • wolf1728
Were you taught to use the quadratic formula?
misty1212
  • misty1212
or how to solve ? once you have \[(3x-7)(x+1)=0\] set each factor equal to zero and solve for \(x\) so \[x+1=0\\ x=-1\] and \[3x-7=0\\ 3x=7\\ x=\frac{7}{3}\]
anonymous
  • anonymous
thats what i did and i got the answers right
wolf1728
  • wolf1728
So, everything's okay Cheyenne?

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