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anonymous

  • one year ago

3x^2=2x=2x+7

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  1. anonymous
    • one year ago
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    too many equal signs

  2. misty1212
    • one year ago
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    HI!!

  3. misty1212
    • one year ago
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    is it \[3x^2-2x=2x+7\]?

  4. anonymous
    • one year ago
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    3x2 - 2x = 2x + 7 ⇒ x=2.333 , x=-1 am I right

  5. anonymous
    • one year ago
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    no

  6. anonymous
    • one year ago
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    wat did I do wrong

  7. anonymous
    • one year ago
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    \[\frac{7}{3}\neq 2.333\]

  8. anonymous
    • one year ago
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    @misty1212 the problem is 3x^2-2x=2x+7

  9. misty1212
    • one year ago
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    subtract \(2x+7\) from both sides to set it equal to zero, and solve\[3x^2-4x-7=0\] by factoring

  10. misty1212
    • one year ago
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    i am bad at factoring, but i think it factors as \[(3x-7)(x+1)=0\]

  11. misty1212
    • one year ago
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    as a matter of fact, i am sure it does

  12. anonymous
    • one year ago
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    yes the answers are right because my teacher gives us the answers but we have to show the work and she doesn't really teach us so i never know who to do the homework

  13. misty1212
    • one year ago
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    are you asking how to factor it?

  14. wolf1728
    • one year ago
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    Were you taught to use the quadratic formula?

  15. misty1212
    • one year ago
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    or how to solve ? once you have \[(3x-7)(x+1)=0\] set each factor equal to zero and solve for \(x\) so \[x+1=0\\ x=-1\] and \[3x-7=0\\ 3x=7\\ x=\frac{7}{3}\]

  16. anonymous
    • one year ago
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    thats what i did and i got the answers right

  17. wolf1728
    • one year ago
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    So, everything's okay Cheyenne?

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