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they really got you factoring, don't they?

yes i took algebra 3 and this is all we are doing is factoring

algebra 3? i didnt know they had that many algebras?

neither did i until i went to this school

try \[(3x-4)(x+1)=0\]

You can use quadratic equation also.....

sure but that is more complicated, my guess is since one factors, they all factor

I agree with Misty's factorisation...... that's more easy....

do you know what to do once you have \[(3x-4)(x+1)=0\]?

it worked thank you @misty1212

\[\color\magenta\heartsuit\]

i have one more problem if you don't mind helping :)

not at all happy to

\[6x^2-13x+6=0\]

bet we can factor this one too huh?

\[(2 x-3) (3 x-2) = 0\] seems to work

use this b=-13 a=6 and c=6

that is why i like to cheat
makes life easier
this is all donkey work anyways

thank you so much for the help :)