3x^2-x-4=0

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they really got you factoring, don't they?
yes i took algebra 3 and this is all we are doing is factoring
algebra 3? i didnt know they had that many algebras?

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neither did i until i went to this school
try \[(3x-4)(x+1)=0\]
You can use quadratic equation also.....
sure but that is more complicated, my guess is since one factors, they all factor
I agree with Misty's factorisation...... that's more easy....
do you know what to do once you have \[(3x-4)(x+1)=0\]?
it worked thank you @misty1212
\[\color\magenta\heartsuit\]
i have one more problem if you don't mind helping :)
not at all happy to
\[6x^2-13x+6=0\]
bet we can factor this one too huh?
yeah pretty sure . my problem is trying to figure out what plus what would equal them middle number , and that would also equal the last number if multiplied
\[(2 x-3) (3 x-2) = 0\] seems to work
use this b=-13 a=6 and c=6
it is not that easy to figure out people claim they have methods, but the methods amount to trial an error anyways
that is why i like to cheat makes life easier this is all donkey work anyways
thank you so much for the help :)

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