anonymous
  • anonymous
rationalize the denominator and simplify (2√7+3)/(√7+2)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
When you want to rationalize the denominator you want to multiply it by the numerator and denominator by the conjugate \[\sqrt{7}-2\]
anonymous
  • anonymous
\[\frac{ (2\sqrt{7}+3 )}{ (\sqrt{7}+2 )} \times \frac{ \sqrt{7}-2 }{ \sqrt{7}-2 }\]
anonymous
  • anonymous
why is it negative? shouldnt it be positive 2?

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anonymous
  • anonymous
oh opps just kidding the bottom cancels out
anonymous
  • anonymous
To rationalize we use the conjugate which simply means we change the sign so notice how we want to rationalize the denominator so we multiply the top and bottom by sqrt(7)-2 we change the + to - this way we can get an expression as such \[a^2-b^2\]
anonymous
  • anonymous
Yeah!
UsukiDoll
  • UsukiDoll
"When you want to rationalize the denominator you want to multiply it by the numerator and denominator by the conjugate " signs need to be switched.. since you have a + on the denominator we have to multiply by sqrt{7}-2
anonymous
  • anonymous
ahaha I understand now! thank you both!

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