A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

check my answer please. Suppose that the functions p and q are defined as follows. p(x)=x^2+3 q(x)=sqrt(x+2) find (q*p)(2)=[?] and (p*q)(2)=[?] I got (q*p)(2)=sqrt 10 and (p*q)(2)=8

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[p(x)=x^2+3\]\[q(x)=\sqrt{x+2}\] \[(qp)(x)=q(x) \times p(x)\] \[pq(x)=p(x) \times q(x)\] Since multiplication is commutative, I don't understand how you are getting different answers

  2. UsukiDoll
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    this could be a composite function question like (q o p) (x) or (p o q)(x) ?

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I was thinking that too, let me check your answers @Kimes

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sorry yes (q o p) (x) or (p o q)(x) i the right format

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I think your answers are incorrect @Kimes , both of them

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    well I followed the steps shown in my book, can you explain then

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Can you show me your steps, how you've attempted the question?

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (q o p) q(p(2)) q(2^2+3) q(7) sqrt 7+3= sqrt 10 (p o q) p(q(2)) p(sqrt 2+3) p(sqrt 5) (sqrt 5)^2+3=8

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I see the mistake now, let me ask you first what is your q(x)? \[q(x)=\sqrt{x+2}\] \[q(x)=\sqrt{x+3}\] Because in the question you've said sqrt{x+2} but in the solution you've used sqrt{x+3}

  10. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ahh I made a silly mistake! thanks for catching it!

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You're welcome, your method of doing the question is perfectly fine, which is good as that means you've grasped the concept, only thing is you made a calculation mistake, that's not a big problem you just have to be careful

  12. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.