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anonymous
 one year ago
check my answer please.
Suppose that the functions p and q are defined as follows.
p(x)=x^2+3
q(x)=sqrt(x+2)
find (q*p)(2)=[?] and (p*q)(2)=[?]
I got (q*p)(2)=sqrt 10 and (p*q)(2)=8
anonymous
 one year ago
check my answer please. Suppose that the functions p and q are defined as follows. p(x)=x^2+3 q(x)=sqrt(x+2) find (q*p)(2)=[?] and (p*q)(2)=[?] I got (q*p)(2)=sqrt 10 and (p*q)(2)=8

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[p(x)=x^2+3\]\[q(x)=\sqrt{x+2}\] \[(qp)(x)=q(x) \times p(x)\] \[pq(x)=p(x) \times q(x)\] Since multiplication is commutative, I don't understand how you are getting different answers

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1this could be a composite function question like (q o p) (x) or (p o q)(x) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I was thinking that too, let me check your answers @Kimes

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry yes (q o p) (x) or (p o q)(x) i the right format

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think your answers are incorrect @Kimes , both of them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well I followed the steps shown in my book, can you explain then

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you show me your steps, how you've attempted the question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(q o p) q(p(2)) q(2^2+3) q(7) sqrt 7+3= sqrt 10 (p o q) p(q(2)) p(sqrt 2+3) p(sqrt 5) (sqrt 5)^2+3=8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I see the mistake now, let me ask you first what is your q(x)? \[q(x)=\sqrt{x+2}\] \[q(x)=\sqrt{x+3}\] Because in the question you've said sqrt{x+2} but in the solution you've used sqrt{x+3}

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ahh I made a silly mistake! thanks for catching it!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You're welcome, your method of doing the question is perfectly fine, which is good as that means you've grasped the concept, only thing is you made a calculation mistake, that's not a big problem you just have to be careful
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