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anonymous
 one year ago
(5c4d)/(2c)(8c7d)/(3c)+4 write as a single fraction
anonymous
 one year ago
(5c4d)/(2c)(8c7d)/(3c)+4 write as a single fraction

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ (5c4d) }{ 2c }\frac{ (8c7d) }{ 3c }+4\] is this your expression?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You may use the following \[\frac{ a }{ b } \pm \frac{ c }{ d } = \frac{ ad \pm bc }{ bd }\] try it out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry am i cross multiplying?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The \[\pm \] implies it works for either sign

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so without much simplifying, its 5c4d(3c)±2c(8c7d)/2c(3c)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's just like adding/ subtracting regular fractions :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So yes you did it right!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0except you don't have to write p/m I was just stating it would work for either sign

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay, but wouldnt the denominator be 6c?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 3c(5c4d) 2c(8c7d)}{ (2c)(3c) }+4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Close but you have \[6c^2\]for the denominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0opps haha forgot the ^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Keep going, you're on the right track

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so I got 15c^212cd16c^214cd/6c^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would I now just simplify it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes keep simplifying and watch the signs \[\frac{ 3c(5c4d) 2c(8c7d)}{ (2c)(3c) }+4 \implies \frac{ 15c^212cd16c^2 \color{red}+14cd }{ 6c^2 }+4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so I got 1c^2+2cd/6c^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ c^2+2cd }{ 6c^2 }+4\] looks good! You can do the same thing with the 4 now, \[4 = \frac{ 4 }{ 1 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and so i multiply 4 by 6c^2 to get a common denominator?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The denominator will stay as 6c^2 you just have to multiply 4 by 6c^2 in the numerator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ c^2+2cd }{ 6c^2 }+4 \implies \frac{ c^2+2cd+4(6c^2) }{ 6c^2 } \implies \frac{ c^2+2cd+24c^2 }{ 6c^2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for final answer I got 23c^2+2cd/6c^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That works but we can simplify it more \[\frac{ 23c^2+2cd }{ 6c^2 } = \frac{ c(23c+2d) }{ 6c^2 } = \frac{ 23c+2d }{ 6c }\] notice we factored out a c.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It looks much more clean this way :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0does the c cancel in 23c and 6c?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah that c got cancelled out so we're left with just 1 c, so here \[\frac{ 23c^2+2cd }{ 6c^2 } = \frac{ \cancel c(23c+2d) }{ 6c^{\cancel 2} } = \frac{ 23c+2d }{ 6c }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ c }{ c^2 } = \frac{ 1 }{ c }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh.. that makes it clear, haha my gosh thank you so much!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Also try that rule I showed you above with regular fractions and you will see it's the exact same thing as adding or subtracting fractions, just a quick little rule. :) So you can even use it for something like \[\frac{ 1 }{ 3 } + \frac{ 4 }{ 5 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it was very helpful, much easier to understand compared to what my teacher taught me :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, sometimes teachers do that...these days they complicate a lot of things which come from simple things as I showed you above ^.^

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0super helpful, thank you so so much!
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