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anonymous
 one year ago
A Daredevil Jumps Off A Tall Building. He Falls Freely For Several Seconds Before Releasing His Parachute . His Height (h) In Meters , T Seconds After Jumping Can Be Modeled By : h=4.9t^2+t+360 before he releases his parachute and h=4t+142 After He Releases His Parachute . How Long After Jumping Did He Release His Parachute ? HELPP ME PLEASE !!!!
anonymous
 one year ago
A Daredevil Jumps Off A Tall Building. He Falls Freely For Several Seconds Before Releasing His Parachute . His Height (h) In Meters , T Seconds After Jumping Can Be Modeled By : h=4.9t^2+t+360 before he releases his parachute and h=4t+142 After He Releases His Parachute . How Long After Jumping Did He Release His Parachute ? HELPP ME PLEASE !!!!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0PLEASE HELP ! THIS IS A BIG QUESTION WORTH LOSTS OF POINTS

NoelGreco
 one year ago
Best ResponseYou've already chosen the best response.0Although it doesn't say so, the second equation suggests he's landed. Solve for t.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok So 4.9t + t + 360=4t +142

NoelGreco
 one year ago
Best ResponseYou've already chosen the best response.0Actually, I put my glasses on an d saw that all you have to do is assume the h valuues are the same, equate the to equations, and solve for t

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0you have \( h_1=4.9t^2+t+360\) \(h_1(0) = 360\) he jumped off a 360m tall building and then you have \(h_2=4t+142\) \(h_2(0) = 142\) he pulled the chute at 142 m above ground so go back to \(h_1(t)\) and work out how long it took him to fall from 360m to 142m you have a quadratic to solve
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