A Daredevil Jumps Off A Tall Building. He Falls Freely For Several Seconds Before Releasing His Parachute . His Height (h) In Meters , T Seconds After Jumping Can Be Modeled By : h=-4.9t^2+t+360 before he releases his parachute and h=-4t+142 After He Releases His Parachute . How Long After Jumping Did He Release His Parachute ? HELPP ME PLEASE !!!!
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PLEASE HELP ! THIS IS A BIG QUESTION WORTH LOSTS OF POINTS
Although it doesn't say so, the second equation suggests he's landed. Solve for t.
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Actually, I put my glasses on an d saw that all you have to do is assume the h valuues are the same, equate the to equations, and solve for t
\(h_1(0) = 360\)
he jumped off a 360m tall building
and then you have
\(h_2(0) = 142\)
he pulled the chute at 142 m above ground
so go back to \(h_1(t)\) and work out how long it took him to fall from 360m to 142m
you have a quadratic to solve