anonymous
  • anonymous
Write the quadratic function in the form f(x)=a−(x-h)^ 2+k . Then, give the vertex of its graph.f(x)=-2x^2+8x-5
Mathematics
schrodinger
  • schrodinger
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zzr0ck3r
  • zzr0ck3r
\(f(x) = ax^2+bx+c\) is the same thing as \(f(x) =a(x+\dfrac{b}{2a})^2+c-a(\dfrac{b}{2a})^2 \)
anonymous
  • anonymous
so i just plug it in?
Sepeario
  • Sepeario
isn't the x point for the vertex -b/2a?

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misty1212
  • misty1212
hi!!
misty1212
  • misty1212
this is not that hard it is \[f(x)=-2x^2+8x-5\]right?
anonymous
  • anonymous
yes
misty1212
  • misty1212
you want to write it as \[f(x)=a(x-h)^2+k\] all you need is \(h\) and \(k\)
misty1212
  • misty1212
since evidently \(a=-2\)
misty1212
  • misty1212
to find \(h\) compute \(-\frac{b}{2a}\) which, in your case, is \(-\frac{8}{2\times (-2)}\)
misty1212
  • misty1212
what do you get ?
anonymous
  • anonymous
is it -8/4x? and simplify so its -2x?
anonymous
  • anonymous
or is it 2/x
anonymous
  • anonymous
it's just 2 Kimes
anonymous
  • anonymous
oh opps i mistaken x and a variable
anonymous
  • anonymous
as*
zzr0ck3r
  • zzr0ck3r
@Kimes yes just plug things :)

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