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anonymous

  • one year ago

Find the points on the x - axis whose distance from the point A(7,6) and B(-3,5) are in the ratio 1:2

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  1. anonymous
    • one year ago
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    @Nishant_Garg

  2. ganeshie8
    • one year ago
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    |dw:1439893212046:dw|

  3. anonymous
    • one year ago
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    Let the coordinates of the point be given by x and y distance between A and the point is given by \[d_{1}=\sqrt{(x-x_{A})^2+(y-y_{A})^2}\] where xA and yA are coordinates of the point A similarly distance between B and the point xB and yB coordinates of point B \[d_{2}=\sqrt{(x-x_{B})^2+(y-y_{B})^2}\] \[\frac{d_{1}}{d_{2}}=\frac{1}{2}\] solve it further

  4. anonymous
    • one year ago
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    ???

  5. anonymous
    • one year ago
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    Do you know the distance formula ??

  6. anonymous
    • one year ago
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    yes

  7. anonymous
    • one year ago
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    What I've done is simply used the distance formula...

  8. anonymous
    • one year ago
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    ok

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