anonymous
  • anonymous
The two lines 3x-y-1=0 and x+3y-5=0 are: a) perpendicular b) parallel c) confounded d) collinear
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
IrishBoy123
  • IrishBoy123
you might wish to compare their slopes re-writing each as \(y = ...\) would help you do that
anonymous
  • anonymous
i got x=3/5. and y=4/5. but now no idea how to continue
Sepeario
  • Sepeario
Is confounded points even a thing?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
the right answer is a- but how to know if 2 lines are perp/paral/conf ?
IrishBoy123
  • IrishBoy123
what you have done is found *incorrectly* the intersection point. plug your answer back into both equations to see. as i said, if you re-write both equations in \(y = mx + c\) form, you will see m, ie the slope, for each. we can go from there. [and i know that n some countries they use \(y = ax + b\) or \(y = mx + b\) but do that first....]
IrishBoy123
  • IrishBoy123
@Sepeario i don't think so. i actually looked it up :p
anonymous
  • anonymous
oki so i got the first y1=3x-1 and y2=(-x/3)-(5/3) what is the next step?
IrishBoy123
  • IrishBoy123
y2 has an error in it but this is the missing bit of information you need when you multiply the slopes of lines that are perpendicular, you get -1 https://gyazo.com/1fa13ef12ef26796eab06a832615537a
anonymous
  • anonymous
ohhh thank you so much you were so helpful. A little more question, how to know if they are parallel?
phi
  • phi
FYI, you should get the equations \[ y = 3x -1 \\y= -\frac{1}{3} x + \frac{5}{3} \] compare the slopes: if they are the same the lines are parallel (unless you have the exact same equation for both, in which case they are the same line) if the slopes are *negative reciprocals*, the lines are perpendicular (form a right angle where they cross) negative reciprocal means "flip" and multiply by -1 for examples: 2/3 and -3/2 (first flip 2/3 to get 3/2 , then negate to get -3/2) or 2 and -1/2 : flip 2 (think of it as 2/1) to get 1/2 , then negate: -1/2 or -1/4 and 4 etc the other test is if you multiply them you get -1 as Irish explained up above

Looking for something else?

Not the answer you are looking for? Search for more explanations.