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anonymous
 one year ago
The two lines 3xy1=0 and x+3y5=0 are:
a) perpendicular
b) parallel
c) confounded
d) collinear
anonymous
 one year ago
The two lines 3xy1=0 and x+3y5=0 are: a) perpendicular b) parallel c) confounded d) collinear

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3you might wish to compare their slopes rewriting each as \(y = ...\) would help you do that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got x=3/5. and y=4/5. but now no idea how to continue

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is confounded points even a thing?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the right answer is a but how to know if 2 lines are perp/paral/conf ?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3what you have done is found *incorrectly* the intersection point. plug your answer back into both equations to see. as i said, if you rewrite both equations in \(y = mx + c\) form, you will see m, ie the slope, for each. we can go from there. [and i know that n some countries they use \(y = ax + b\) or \(y = mx + b\) but do that first....]

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3@Sepeario i don't think so. i actually looked it up :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oki so i got the first y1=3x1 and y2=(x/3)(5/3) what is the next step?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3y2 has an error in it but this is the missing bit of information you need when you multiply the slopes of lines that are perpendicular, you get 1 https://gyazo.com/1fa13ef12ef26796eab06a832615537a

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh thank you so much you were so helpful. A little more question, how to know if they are parallel?

phi
 one year ago
Best ResponseYou've already chosen the best response.0FYI, you should get the equations \[ y = 3x 1 \\y= \frac{1}{3} x + \frac{5}{3} \] compare the slopes: if they are the same the lines are parallel (unless you have the exact same equation for both, in which case they are the same line) if the slopes are *negative reciprocals*, the lines are perpendicular (form a right angle where they cross) negative reciprocal means "flip" and multiply by 1 for examples: 2/3 and 3/2 (first flip 2/3 to get 3/2 , then negate to get 3/2) or 2 and 1/2 : flip 2 (think of it as 2/1) to get 1/2 , then negate: 1/2 or 1/4 and 4 etc the other test is if you multiply them you get 1 as Irish explained up above
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