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anonymous
 one year ago
How do i factor 8x^2y^3+4x^2y^22xy?
anonymous
 one year ago
How do i factor 8x^2y^3+4x^2y^22xy?

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butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1You want to find the HCF :) So you can break this down by just looking at the numbers first: 8 , 4 and 2 What would the HCF of 2,4 and 8 be?

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1hint: Factors of 2 = 1,2 Factors of 4 = 1, 2, 4 Factors of 8 = 1, 2 , 4 , 8

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1yess. So factorise out 2 and we get: \[8x^2y^3+4x^2y^22xy\] \[= 2 (4x^2 y^3  2x^2y^2 xy) \] Now look at the x's :) We have x, x^2 and x^2 So what would be the HCF of those? Note: factors of x = 1, x Factors of x^2 = 1, x , x^2
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