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anonymous

  • one year ago

A box has 8 beads of the same size, but all are different colors. Tamy draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tamy would pick a red bead on the first draw, then a white bead, and finally a red bead again? 1 over 4096 1 over 512 1 over 64 1 over 8

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  1. misty1212
    • one year ago
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    she puts them back each time right?

  2. anonymous
    • one year ago
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    yes

  3. misty1212
    • one year ago
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    and the beads are all different colors, so 8 different colors the probability of any one color is therefore \(\frac{1}{8}\)

  4. misty1212
    • one year ago
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    that is not the final answer though

  5. anonymous
    • one year ago
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    oh ok

  6. misty1212
    • one year ago
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    do it 3 times in a row, the probability of red, white, red is\[\frac{1}{8}\times \frac{1}{8}\times \frac{1}{8}\]

  7. misty1212
    • one year ago
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    use a calculator to compute \[8^3\] then put it in the denominator

  8. anonymous
    • one year ago
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    ok...i got 512 when i multiplied that so now what? @misty1212

  9. anonymous
    • one year ago
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    oh so is my answer 1/512 @misty1212

  10. misty1212
    • one year ago
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    yes dear that is right

  11. anonymous
    • one year ago
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    thank you! ^_^

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