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anonymous

  • one year ago

In a titration, 25.0 mL of 0.500 M KHP is titrated to the equivalence point with NaOH. The final solution volume is 53.5 mL. What is the value of M1 for the reaction? 25 0.5 53.5 28.5

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  1. taramgrant0543664
    • one year ago
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    m1v1=m2v2 m1=(m2v2)/v1 Where m is the molarities and v is the volumes

  2. anonymous
    • one year ago
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    I keep getting 1.07? :/ @taramgrant0543664

  3. taramgrant0543664
    • one year ago
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    Ya me too KHC8H4O4(aq) + NaOH(aq) → KNaC8H4O4(aq) + H2O(l) Is the balanced formula so they are in a 1:1 ratio because of the stoichiometric coefficients So the moles remain constant n=mv, n is the moles, m is molarity, v is volume so since the moles are constant you can use the m1v1=m2v2

  4. taramgrant0543664
    • one year ago
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    I really don't think any of those options are right unless I'm complete screwing it up which I could be since I just woke up, lol let me tag a few people they might be able to figure it out

  5. taramgrant0543664
    • one year ago
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    @nechirwan @arindameducationusc

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