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anonymous
 one year ago
In a titration, 25.0 mL of 0.500 M KHP is titrated to the equivalence point with NaOH. The final solution volume is 53.5 mL. What is the value of M1 for the reaction?
25
0.5
53.5
28.5
anonymous
 one year ago
In a titration, 25.0 mL of 0.500 M KHP is titrated to the equivalence point with NaOH. The final solution volume is 53.5 mL. What is the value of M1 for the reaction? 25 0.5 53.5 28.5

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taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.0m1v1=m2v2 m1=(m2v2)/v1 Where m is the molarities and v is the volumes

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I keep getting 1.07? :/ @taramgrant0543664

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.0Ya me too KHC8H4O4(aq) + NaOH(aq) → KNaC8H4O4(aq) + H2O(l) Is the balanced formula so they are in a 1:1 ratio because of the stoichiometric coefficients So the moles remain constant n=mv, n is the moles, m is molarity, v is volume so since the moles are constant you can use the m1v1=m2v2

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.0I really don't think any of those options are right unless I'm complete screwing it up which I could be since I just woke up, lol let me tag a few people they might be able to figure it out

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.0@nechirwan @arindameducationusc
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