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anonymous

  • one year ago

The prices of some jewelry sets in a store are shown below: Store Price A $110,000 B $100,000 C $1,110,000 D $130,000 E $120,000 Based on the data, should the mean or the median be used to make an inference about the price of the jewelry sets in the store? Mean, because it is in the center of the data Median, because it is in the center of the data Median, because there is an outlier that affects the mean Mean, because there are no outliers that affect the mean

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  1. anonymous
    • one year ago
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    @mathstudent55

  2. anonymous
    • one year ago
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    There's outlier in your data set

  3. iYuko
    • one year ago
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    How does the book tell you to do this?

  4. anonymous
    • one year ago
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    there is no book

  5. iYuko
    • one year ago
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    the lesson

  6. anonymous
    • one year ago
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    mean is skewed by the outlier in the data set

  7. iYuko
    • one year ago
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    Show me the work @Kim21

  8. iYuko
    • one year ago
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    I will tell you if it's right.

  9. anonymous
    • one year ago
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    but i dont know how to do this :(

  10. anonymous
    • one year ago
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    yup no direct answer!

  11. iYuko
    • one year ago
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    You need to review

  12. iYuko
    • one year ago
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    What test is this?

  13. anonymous
    • one year ago
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    think back whats mean and median

  14. anonymous
    • one year ago
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    its a pretest so its just to see what i know so i haven't learned this yet but i want to still get the right answer cause it counts towards grade ;b

  15. anonymous
    • one year ago
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    median is the middle number of the data set and mean is when u add and divide the numbers in the data set

  16. anonymous
    • one year ago
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    The mean is the average of the numbers.

  17. anonymous
    • one year ago
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    yes so mean is\[Mean = \frac{ x_1 + x_2 +...+ x_n }{ n } \]

  18. anonymous
    • one year ago
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    what do you think happens if 1 of the x is a huge number

  19. anonymous
    • one year ago
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    not sure :?

  20. anonymous
    • one year ago
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    the means becomes skewed by that large x

  21. anonymous
    • one year ago
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    @mathstudent55

  22. anonymous
    • one year ago
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    you made any progress so far?

  23. anonymous
    • one year ago
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    no im gonna call @mathstudent55 for some help but thanks anways :)

  24. anonymous
    • one year ago
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    read this http://www.quickmba.com/stats/centralten/

  25. anonymous
    • one year ago
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    you might find your answer there

  26. anonymous
    • one year ago
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    ok thanks! :)

  27. mathstudent55
    • one year ago
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    An outlier affects more the mean that the median. When you have outliers, using the median instead of the mean may give you a better picture of how the data is distributed.

  28. mathstudent55
    • one year ago
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    See the great explanation here: https://www.mathsisfun.com/data/outliers.html

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