anonymous
  • anonymous
The prices of some jewelry sets in a store are shown below: Store Price A $110,000 B $100,000 C $1,110,000 D $130,000 E $120,000 Based on the data, should the mean or the median be used to make an inference about the price of the jewelry sets in the store? Mean, because it is in the center of the data Median, because it is in the center of the data Median, because there is an outlier that affects the mean Mean, because there are no outliers that affect the mean
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@mathstudent55
anonymous
  • anonymous
There's outlier in your data set
iYuko
  • iYuko
How does the book tell you to do this?

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More answers

anonymous
  • anonymous
there is no book
iYuko
  • iYuko
the lesson
anonymous
  • anonymous
mean is skewed by the outlier in the data set
iYuko
  • iYuko
Show me the work @Kim21
iYuko
  • iYuko
I will tell you if it's right.
anonymous
  • anonymous
but i dont know how to do this :(
anonymous
  • anonymous
yup no direct answer!
iYuko
  • iYuko
You need to review
iYuko
  • iYuko
What test is this?
anonymous
  • anonymous
think back whats mean and median
anonymous
  • anonymous
its a pretest so its just to see what i know so i haven't learned this yet but i want to still get the right answer cause it counts towards grade ;b
anonymous
  • anonymous
median is the middle number of the data set and mean is when u add and divide the numbers in the data set
anonymous
  • anonymous
The mean is the average of the numbers.
anonymous
  • anonymous
yes so mean is\[Mean = \frac{ x_1 + x_2 +...+ x_n }{ n } \]
anonymous
  • anonymous
what do you think happens if 1 of the x is a huge number
anonymous
  • anonymous
not sure :?
anonymous
  • anonymous
the means becomes skewed by that large x
anonymous
  • anonymous
@mathstudent55
anonymous
  • anonymous
you made any progress so far?
anonymous
  • anonymous
no im gonna call @mathstudent55 for some help but thanks anways :)
anonymous
  • anonymous
read this http://www.quickmba.com/stats/centralten/
anonymous
  • anonymous
you might find your answer there
anonymous
  • anonymous
ok thanks! :)
mathstudent55
  • mathstudent55
An outlier affects more the mean that the median. When you have outliers, using the median instead of the mean may give you a better picture of how the data is distributed.
mathstudent55
  • mathstudent55
See the great explanation here: https://www.mathsisfun.com/data/outliers.html

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