The prices of some jewelry sets in a store are shown below: Store Price A $110,000 B $100,000 C $1,110,000 D $130,000 E $120,000 Based on the data, should the mean or the median be used to make an inference about the price of the jewelry sets in the store? Mean, because it is in the center of the data Median, because it is in the center of the data Median, because there is an outlier that affects the mean Mean, because there are no outliers that affect the mean

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The prices of some jewelry sets in a store are shown below: Store Price A $110,000 B $100,000 C $1,110,000 D $130,000 E $120,000 Based on the data, should the mean or the median be used to make an inference about the price of the jewelry sets in the store? Mean, because it is in the center of the data Median, because it is in the center of the data Median, because there is an outlier that affects the mean Mean, because there are no outliers that affect the mean

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There's outlier in your data set
How does the book tell you to do this?

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Other answers:

there is no book
the lesson
mean is skewed by the outlier in the data set
Show me the work @Kim21
I will tell you if it's right.
but i dont know how to do this :(
yup no direct answer!
You need to review
What test is this?
think back whats mean and median
its a pretest so its just to see what i know so i haven't learned this yet but i want to still get the right answer cause it counts towards grade ;b
median is the middle number of the data set and mean is when u add and divide the numbers in the data set
The mean is the average of the numbers.
yes so mean is\[Mean = \frac{ x_1 + x_2 +...+ x_n }{ n } \]
what do you think happens if 1 of the x is a huge number
not sure :?
the means becomes skewed by that large x
you made any progress so far?
no im gonna call @mathstudent55 for some help but thanks anways :)
read this http://www.quickmba.com/stats/centralten/
you might find your answer there
ok thanks! :)
An outlier affects more the mean that the median. When you have outliers, using the median instead of the mean may give you a better picture of how the data is distributed.
See the great explanation here: https://www.mathsisfun.com/data/outliers.html

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