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A train covered a certain distance at a uniform speed.if the train would have been 10km/h faster , it would have taken 2 hours less than the schedules time.and if the train were slower by 10km/h ; it would have taken 3 hours more than scheduled time.find the distance covered by the train
@Preetha and @pooja195 PLS HELP
Hi! Don't cry, let's try to solve this together c:
Train is travelling with uniform speed, so first thing you need to know is that when anything is travelling through constant speed then distance traversed is given by speed*time.
So, we can say that time taken is given by distance/speed. Got it?
Let the speed of train be s and distance be d. Then time taken will be d/s ........ 1 Now, if train would have been 10 km/hr faster then its speed would be (s+10) and time taken would be (T-2). So we can write that d/(x+10) = T-2 .......2
Again, if the train would have been 10km/h slower then its speed would have been (s-10) and time taken would have been (T+3) So, we can write that d/(s-10)=T+3
Now, you have 3 variables d, s and T and 3 equations. Can you solve the equations to find the value of variables?
i dont knw to solve three i only knw to solve 2
Ok, I'll help you. From equation 1 we know d=st. Now put this value of d in other two equations and solve the 2 equations. Can you do that?
\(\bf Hint\) Value of S will be 50 km/h
ok let me try
am not getting it
We will get following two equations, st = (T-2)(s+10) st = (T+3)(s-10) Simplifying both of them and then adding. |dw:1439948695514:dw|
Thank uh :)