A community for students.
Here's the question you clicked on:
 0 viewing
Lena772
 one year ago
Determine the Molarity (M, moles solute / Liter of solution) of a solution formed when 2.134E3 kg Aluminum chloride is dissolved in water such that the final volume of the solution is 0.4356 kL.
Lena772
 one year ago
Determine the Molarity (M, moles solute / Liter of solution) of a solution formed when 2.134E3 kg Aluminum chloride is dissolved in water such that the final volume of the solution is 0.4356 kL.

This Question is Closed

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0I know how to find Molarity but I'm not sure where the final volume comes in in the equation. Help? Thanks. :)

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0@mathstudent55 @Abhisar @Nnesha

cuanchi
 one year ago
Best ResponseYou've already chosen the best response.3Molarity is equal to moles of solute per liter of solution. The problem is giving you a mass of Aluminum chloride in kg, this is the solute of your solution. You have to calculate how many moles of Aluminum chloride are in 2.134E3 kg Aluminum chloride. You will need the molecular mas of Aluminum chloride. Then divide this value by the volume of your solution (0.4356 kL) converted in liters. That will be the molarity of the solution

cuanchi
 one year ago
Best ResponseYou've already chosen the best response.3did you got the answer? what value did you get?

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0Ok I did (2134g AlCl3*1 mol AlCl3)/133.3405gAlCl3 = 16.004molAlCl3. I'm confused to where I go from here.

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0Would it be 16.004molAlCl3/435.6L = 0.03674 mol/L

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0Is my answer right? @dan815 @TheSmartOne @Nnesha @Luigi0210 @whpalmer4 @compassionate @abb0t @mathmate @KyanTheDoodle

cuanchi
 one year ago
Best ResponseYou've already chosen the best response.3the procedure is correct the only problem that I see is the conversion from kg to g 2.134E3 kg = 2.134 g

TheSmartOne
 one year ago
Best ResponseYou've already chosen the best response.0I'm not that good in Chemistry, unfortunately ;; @JoannaBlackwelder @chmvijay @Abhisar @matt101 @Australopithecus @alphadxg can assist you better in chem :)

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0@Cuanchi (2.134 g AlCl3 * 1 mol AlCl3) / 133.3405 g AlCl3 = 0.016004 mol AlCl3 0.016004 mol AlCl3/ 435.6 L AlCl3 = 0.00003674 mol/L

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0@Lena772 Just a guess, can you check if the volume of solution is 0.4536kL or 0.4356kL?

Lena772
 one year ago
Best ResponseYou've already chosen the best response.0It's 0.4356 @mathmate!

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0Thank you, your calculation remains perfect! :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.