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anonymous

  • one year ago

What is the value of the expression? 5^-6*5^2 ---------- 5^-8 A. 5^−20 B. 5^−12 C. 5^4 D. 5^-4

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  1. Nnesha
    • one year ago
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    exponent rule \[\huge\rm \frac{ x^m }{ x^n }=x^{m-n}\] there is negative exponent in the denominator so move that to the top

  2. anonymous
    • one year ago
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    ....

  3. Nnesha
    • one year ago
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    sorry i don't understand dot language.

  4. anonymous
    • one year ago
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    lol sorry It's just I don't get it :'(

  5. Nnesha
    • one year ago
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    basses are same so just transfer -8 to the top here is an example \[\large\rm \frac{ 2^3 }{ 2^{-5} } = x^{2\color{red}{+}5}\]

  6. anonymous
    • one year ago
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    ok

  7. Nnesha
    • one year ago
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    and then apply exponent rule \[\huge\rm x^m \times x^n = x^{m+n}\]when you multiply same bases you should add their exponents

  8. anonymous
    • one year ago
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    ok

  9. Nnesha
    • one year ago
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    so what did you get ?

  10. anonymous
    • one year ago
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    7?

  11. Nnesha
    • one year ago
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    how did you get that ?

  12. anonymous
    • one year ago
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    2+5

  13. anonymous
    • one year ago
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    im so wrong! I'm sorry i'm being stupid

  14. Nnesha
    • one year ago
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    i know ... reread what i said above then try to solve

  15. anonymous
    • one year ago
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    ill just put d bye

  16. Nnesha
    • one year ago
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    you should familiar with the exponent rules you can't have the negative exponent there \[\huge\rm x^{-m}=\frac{ 1 }{ x^m }\]

  17. anonymous
    • one year ago
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    ???

  18. Nnesha
    • one year ago
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    \[\huge\rm \frac{ \color{Red}{5^{-6} \times 5^{2} }}{ 5^{-8}}= \] first look at the numerator when you multiply same bases you should ADD their exponents \[\large\rm x^m \times x^n = x^{m+n}\]

  19. anonymous
    • one year ago
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    8?

  20. Nnesha
    • one year ago
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    -6+(2) = 8 ?

  21. anonymous
    • one year ago
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    -4

  22. Nnesha
    • one year ago
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    yes right \[\huge\rm \frac{ 5^{-4} }{ 5^{-8}}\] now move the -8 exponent to the top here is an example \[\huge\rm \frac{ x^m }{ x^{n} } = x^{m+(-n)}\]

  23. anonymous
    • one year ago
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    i divide now?

  24. Nnesha
    • one year ago
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    now you don't divide bases are the same right 5 is base and there is negative -8 exponent in the denominator move that to top of the fraction

  25. anonymous
    • one year ago
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    huh

  26. Nnesha
    • one year ago
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    here is an example \[\huge\rm \frac{ 2^{-3} }{ 2^{-9} } = 2^{-3+(-9)}\]

  27. anonymous
    • one year ago
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    Add -3 and -9? -12

  28. Nnesha
    • one year ago
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    that's an example and there is typo wait a sec

  29. anonymous
    • one year ago
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    oh

  30. Nnesha
    • one year ago
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    here is an example \[\huge\rm \frac{ 2^{-3} }{ 2^{-9} } = 2^{-3-(-9)}\]

  31. anonymous
    • one year ago
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    oh subtract?

  32. anonymous
    • one year ago
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    its 6

  33. Nnesha
    • one year ago
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    yes right - times -9 is = positive 9 so -3 +9 now look at ur question \[\huge\rm \frac{ 5^{-4} }{ 5^{-8} }= 5^{???}\]

  34. anonymous
    • one year ago
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    -12

  35. Nnesha
    • one year ago
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    no remember sign would change

  36. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 5^{-4} }{ 5^{-8} }= 5^{-4-(-8)}\]

  37. anonymous
    • one year ago
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    6?

  38. Nnesha
    • one year ago
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    how did you get 6 ?? :O

  39. anonymous
    • one year ago
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    IDK

  40. Nnesha
    • one year ago
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    so why did you say 6 ?? just add the exponent that's it

  41. anonymous
    • one year ago
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    4

  42. Nnesha
    • one year ago
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    \[\huge\rm \frac{ 5^{-4} }{ 5^{-8} }= 5^{\color{Red}{-4-(-8)}}\] know how do solve red part(exponents ?

  43. Nnesha
    • one year ago
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    yes right!!

  44. anonymous
    • one year ago
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    so its c

  45. anonymous
    • one year ago
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    ???

  46. Nnesha
    • one year ago
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    ye...

  47. anonymous
    • one year ago
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    tysm!!!

  48. Nnesha
    • one year ago
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    YW

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