A football quarterback has 2 more chances to throw a touchdown before his team is forced to punt the ball. He misses the receiver on the first throw 30% of the time. When his first throw is incomplete, he misses the receiver on the second throw 10% of the time. What is the probability of not throwing the ball to a receiver on either throw?
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If given two percentages you can treat them as probabilities. This means that 30 percent becomes p=.3 and 10 percent becomes p=.1
If given two probabilities, you can calculate the probability of both occurring by multiplying them.
This means .3*.1=.03 therefore the probability of both occurring is p=.03