anonymous
  • anonymous
check my work
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Find the values of constants a, b and c so that the maximum value of the directional derivative of \[\phi(x,y,z)=axy^2+byz+cz^2x^3\] at (1,2,-1) is 64 in the direction parallel to the z axis Now, \[\vec \nabla \phi(1,2,-1)=(4a+3c)\hat i+(4a-b)\hat j+(-2c)\hat k\] Vector equation of z axis, \[\vec z=0 \hat i+0 \hat j+z \hat k\] Now for the vector to be parallel to z axis it's corresponding components must be a scalar multiple \[\therefore (4a+3c)=\lambda0=0\] \[(4a-b)=\lambda0=0\] \[-2c=\lambda z\] \[|\vec \nabla \phi(1,2,-1)|=\sqrt{(4a+3c)^2+(4a-b)^2+(-2c)^2}=64\] \[|\vec \nabla \phi(1,2,-1)|=\sqrt{\lambda^2.z^2}=64\] \[\implies \lambda.z=\pm64\] \[\lambda=\pm \frac{64}{z}\] \[-2c=\lambda.z=\pm64\]\[c=\mp8\] \[\therefore a=\frac{-3c}{4}=\frac{\pm24}{4}=\pm6\] \[b=4a=\pm24\]
anonymous
  • anonymous
@ganeshie8
anonymous
  • anonymous
@IrishBoy123

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IrishBoy123
  • IrishBoy123
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anonymous
  • anonymous
oh shoot, I missed one term!! but still my answers are holding good, magic lol \[2b-2c\] I've written as -2c How did I not get the wrong answer??amazing
IrishBoy123
  • IrishBoy123
good point, i should have made them \(\pm\) cos it could point up or down the z axis....
anonymous
  • anonymous
Didn't you see my mistake?I still got the right answer though
anonymous
  • anonymous
I just noticed my mistake when I saw your sheet lol
IrishBoy123
  • IrishBoy123
that must be quite some coincidence

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