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anonymous
 one year ago
need help factoring (completely)
x^25x+6
anonymous
 one year ago
need help factoring (completely) x^25x+6

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triciaal
 one year ago
Best ResponseYou've already chosen the best response.1this is in the form ax^2 + bx + c to find factors set = 0 when (xh) is a factor the remainder = 0 h is a number here are the steps to factor: identify your a, b, c find a*c list the factors of a*c including the signs find factors of a*c that will add up to b rewrite the function to "split" b into 2 components regroup the terms and find the common factors use the distributive property

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1can you try or do you want me to do this with you ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a is 1 b is5 and c is 6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know that you can do it this way (x ) (x )

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but i get confused on the middle part (something about the product of the first and last gives the middle...?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1what is the product of a*c?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1what are the factors of 6 then choose the ones that will add up to 5?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1good now rewrite the original with 2 and 3 instead of just 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer would be (x2) (x3)

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1yes but I was showing all the steps to get there

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439918342540:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how did u get to x(x2)3(x2)?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1review the steps I listed with going through the problem

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439918570261:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok i get it, thanx! can u help me with another question?
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