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anonymous

  • one year ago

need help factoring (completely) x^2-5x+6

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  1. anonymous
    • one year ago
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    ?

  2. triciaal
    • one year ago
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    this is in the form ax^2 + bx + c to find factors set = 0 when (x-h) is a factor the remainder = 0 h is a number here are the steps to factor: identify your a, b, c find a*c list the factors of a*c including the signs find factors of a*c that will add up to b rewrite the function to "split" b into 2 components regroup the terms and find the common factors use the distributive property

  3. triciaal
    • one year ago
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    can you try or do you want me to do this with you ?

  4. anonymous
    • one year ago
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    a is 1 b is5 and c is 6

  5. anonymous
    • one year ago
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    i know that you can do it this way (x ) (x )

  6. anonymous
    • one year ago
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    but i get confused on the middle part (something about the product of the first and last gives the middle...?

  7. anonymous
    • one year ago
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    u still ther?

  8. triciaal
    • one year ago
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    check your b

  9. anonymous
    • one year ago
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    oh its -5

  10. triciaal
    • one year ago
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    what is the product of a*c?

  11. anonymous
    • one year ago
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    6

  12. triciaal
    • one year ago
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    what are the factors of 6 then choose the ones that will add up to -5?

  13. anonymous
    • one year ago
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    -2 and -3

  14. triciaal
    • one year ago
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    good now rewrite the original with -2 and -3 instead of just -5

  15. anonymous
    • one year ago
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    so the answer would be (x-2) (x-3)

  16. anonymous
    • one year ago
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    oh x^2-2x-3x+6

  17. triciaal
    • one year ago
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    yes but I was showing all the steps to get there

  18. anonymous
    • one year ago
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    oh ok continue

  19. triciaal
    • one year ago
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    |dw:1439918342540:dw|

  20. anonymous
    • one year ago
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    how did u get to x(x-2)-3(x-2)?

  21. triciaal
    • one year ago
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    review the steps I listed with going through the problem

  22. triciaal
    • one year ago
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    |dw:1439918570261:dw|

  23. anonymous
    • one year ago
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    ok i get it, thanx! can u help me with another question?

  24. triciaal
    • one year ago
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    ok open new post

  25. anonymous
    • one year ago
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    ok

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