a number after the variable is an exponent
here is a reference to help you file:///C:/Users/Owner/Downloads/StudyGuide.IA.pdf
copy and paste if u doof
allo ospreytriple :)
Hi. You need some help? Firstly, for a trinomial to be a perfect square, both the first and last terms must be perfect squares. For example\[\left( 2x+3 \right)\left( 2x+3 \right) = 4x^2+12x+9\]Both the first term, 4x^2, and the last term, 9, are perfect squares. Understand so far?
This will eliminate one of the answers.
Now, to pin it down, The coefficient of the middle term (the coefficient of the 'x' term) must be equal to twice the product of the square roots of the coefficient of the first term and the third term. In my example\[4x^2+12x+9\]the square root of the coefficient of the first term is 2 and the square root of the third term is 3. Twice their product is 2(2 x 3) = 12. OK?
And to make it even trickier, you have to consider that the negative square root may also be a possibility.
Take the first answer given for example. The square root of 49 is +7 or -7 and the square root of 16 is +4 or -4. So, if it is a perfect square the coefficient of the middel term must be one of 2(-7 x 4) 2(-7 x -4) 2(7 x 4) 2(7 x -4) If it is not one of these, the it is not a perfect square trinomial.
BTW these are the answers 49x2 − 8x + 16 4a2 − 10a + 25 25b2 − 5b + 10 16x2 − 8x + 1
Yes. Well done.
THX SO MUCH
Oops. sorry, it's not B.
The middle coefficient must be TWICE the product of the two square roots.
So, for the possibilities for the coefficient of the middle term are 2(-2 x 5) 2(-2 x -5) 2(2 x 5) 2(2 x -5)
Yes, D is correct. Sorry for the mixup.