anonymous
  • anonymous
WILL FAN AND MEDAL Select the polynomial that is a perfect square trinomial. 49x2 − 8x + 16 4a2 − 10a + 25 25b2 − 5b + 10 16x2 − 8x + 1
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
a number after the variable is an exponent
anonymous
  • anonymous
anonymous
  • anonymous

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Taylor0402
  • Taylor0402
here is a reference to help you file:///C:/Users/Owner/Downloads/StudyGuide.IA.pdf
anonymous
  • anonymous
I can't click the link @Taylor0402
Taylor0402
  • Taylor0402
copy and paste if u doof
anonymous
  • anonymous
anonymous
  • anonymous
allo ospreytriple :)
anonymous
  • anonymous
Hi. You need some help? Firstly, for a trinomial to be a perfect square, both the first and last terms must be perfect squares. For example\[\left( 2x+3 \right)\left( 2x+3 \right) = 4x^2+12x+9\]Both the first term, 4x^2, and the last term, 9, are perfect squares. Understand so far?
anonymous
  • anonymous
anonymous
  • anonymous
This will eliminate one of the answers.
anonymous
  • anonymous
Now, to pin it down, The coefficient of the middle term (the coefficient of the 'x' term) must be equal to twice the product of the square roots of the coefficient of the first term and the third term. In my example\[4x^2+12x+9\]the square root of the coefficient of the first term is 2 and the square root of the third term is 3. Twice their product is 2(2 x 3) = 12. OK?
anonymous
  • anonymous
And to make it even trickier, you have to consider that the negative square root may also be a possibility.
anonymous
  • anonymous
Take the first answer given for example. The square root of 49 is +7 or -7 and the square root of 16 is +4 or -4. So, if it is a perfect square the coefficient of the middel term must be one of 2(-7 x 4) 2(-7 x -4) 2(7 x 4) 2(7 x -4) If it is not one of these, the it is not a perfect square trinomial.
anonymous
  • anonymous
BTW these are the answers 49x2 − 8x + 16 4a2 − 10a + 25 25b2 − 5b + 10 16x2 − 8x + 1
anonymous
  • anonymous
@ospreytriple is it B?
anonymous
  • anonymous
anonymous
  • anonymous
Yes. Well done.
anonymous
  • anonymous
THX SO MUCH
anonymous
  • anonymous
Oops. sorry, it's not B.
anonymous
  • anonymous
The middle coefficient must be TWICE the product of the two square roots.
anonymous
  • anonymous
So d
anonymous
  • anonymous
So, for the possibilities for the coefficient of the middle term are 2(-2 x 5) 2(-2 x -5) 2(2 x 5) 2(2 x -5)
anonymous
  • anonymous
Yes, D is correct. Sorry for the mixup.
anonymous
  • anonymous
its ok

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