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- anonymous

Radio signals travel at a rate of 3*10^8 meters per second. How many seconds will it take for a radio signal to travel from a satellite to the surface of the Earth if the satellite is orbiting at a height of 7.5*10^6 meters?
A) 6 seconds
B) 2.5*10^-2 seconds
3) 4.0*10^3 seconds
D) 2.5*10^2 seconds

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- anonymous

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- anonymous

- anonymous

- anonymous

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- anonymous

- JoannaBlackwelder

distance=rate*time

- anonymous

so we solve for rate first? @JoannaBlackwelder

- JoannaBlackwelder

We are given rate. We are looking for time. So, solve for time.

- anonymous

Can u help me with that please @JoannaBlackwelder

- JoannaBlackwelder

|dw:1439920734718:dw| To solve for time, we need to get it by itself.

- JoannaBlackwelder

|dw:1439920766408:dw| r is currently multiplied by t, so we divide by it to get rid of it on that side. And what we do to one side of an equation, we have to do to the other side.

- JoannaBlackwelder

|dw:1439920841491:dw|

- JoannaBlackwelder

Does that make sense so far?

- anonymous

kinda, I get confused with letters in math @JoannaBlackwelder

- JoannaBlackwelder

Ok, yeah, they can be kinda tricky. Let me show you another way that doesn't use letters.

- JoannaBlackwelder

Start with the distance the signal travels:|dw:1439921098416:dw|

- JoannaBlackwelder

|dw:1439921144658:dw| And since the signals travel 3x10^8 meters in 1 second, we can use that ratio as a conversion factor.

- JoannaBlackwelder

Since for the signals 1 second equals 3x10^8 meters of travel

- JoannaBlackwelder

And multiplying by a fraction of two things that are equal is just multiplying by 1, which doesn't change the value.

- JoannaBlackwelder

|dw:1439921324634:dw| The units of m cancel since one is in the numerator and the other is in the denominator.

- JoannaBlackwelder

And we are left with a number of seconds. :-) Does that method make more sense?

- anonymous

It does make more sense.. @JoannaBlackwelder

- JoannaBlackwelder

:-)

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