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k_lynn

  • one year ago

Simplify...

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  1. k_lynn
    • one year ago
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    \[(3x ^{2}+2x +7x ^{3})+(10x ^{2}+6x +9)\] This needs simplified and I'm not sure whre to begin.

  2. k_lynn
    • one year ago
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    @misty1212

  3. kropot72
    • one year ago
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    First step is to remove the brackets. Next gather like terms.

  4. k_lynn
    • one year ago
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    What do you mean by remove the brackets? And when I combine the like terms, do I add the add the exponents?

  5. kropot72
    • one year ago
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    Removing the brackets gives \[\large 3x^{2}+2x+7x^{3}+10x^{2}+6x+9\] The terms in x-squared are like terms. To add the 2 terms in x-squared, just add the coefficients of x-squared (3 + 10 = 13).

  6. k_lynn
    • one year ago
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    Oh, ok. So I have \[13x ^{2}+2x +7x ^{3}+6x +9\]

  7. k_lynn
    • one year ago
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    can I combine 2x and 6x?

  8. kropot72
    • one year ago
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    The terms in x are also like terms. To add them just add the coefficients (2 + 6 = 8).

  9. k_lynn
    • one year ago
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    Right. SO now: \[13x ^{2}+8x+7x ^{3}+9\] And so is that it?

  10. anonymous
    • one year ago
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    The next step is to arrange in decreasing order of powers, not really necessary but yeah.. \[7x^3+13x^2+8x+9\] Looks more nice that way

  11. kropot72
    • one year ago
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    Nearly finished. The last step is to arrange the terms in descending powers of x, starting with x cubed.

  12. k_lynn
    • one year ago
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    Ok, thanks so much everyone!

  13. kropot72
    • one year ago
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    You're welcome :)

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