- anonymous

NEED INSTANT HELP PLEASE PLEASE PLEASE MEDAL AND FAN:
Is the expression x^3timesx^3timesx^3 equivalent to x^3times^3times^3 ? Why or Why not, explain your reasoning.

- katieb

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- xapproachesinfinity

what the heck does x^3times^3times^3 mean?

- anonymous

x to the third multiplied

- xapproachesinfinity

you want what \(x^3.x^3.x^3\)
this is the first part

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## More answers

- anonymous

yes

- xapproachesinfinity

you want to see if it is equivalent to what?

- xapproachesinfinity

use the drawing to write what you meant
that is vague the way you wrote it

- anonymous

ok

- anonymous

|dw:1439924092560:dw|

- xapproachesinfinity

do you mean is it equivalent to \(x^{3\times 3 \times 3 }\)

- anonymous

yes and why

- xapproachesinfinity

it is not equivalent

- xapproachesinfinity

what is x^3?

- xapproachesinfinity

it is xtimesxtimesx right

- anonymous

yes

- xapproachesinfinity

so we have \(x.x.x.x.x.x.x.x.x=?\)

- anonymous

for the first or second equation?

- xapproachesinfinity

i just wrote x^3 as xtimesxtimesx the definition of exponent

- anonymous

because its asking me if the two different equations are equivalent and then why or why not

- xapproachesinfinity

first of course we are trying to see why it is not equivalent to second

- anonymous

ok

- xapproachesinfinity

now accordding to what i did
we should get x^9 for the first (this the definition of exponent)
when we have \(a^n\times a^m=a^{n+m}\)

- xapproachesinfinity

that is why \(x^3\times x^3\times x^3=x^9\)

- anonymous

oh ok so thats the answer for the first one ?

- xapproachesinfinity

now the second is different \(x^{3\times 3\times 3}=x^{27}\)

- anonymous

why did you multiply the exponents on the second one but added them ump on the first?

- xapproachesinfinity

and since x^9 does not equal x^27 then they are not equivalent at all

- xapproachesinfinity

because that is multiplication on the exponent buddy

- anonymous

ok i was just wondering thanks

- xapproachesinfinity

well it said x^{3x3x3} so just multiply

- xapproachesinfinity

no problem

- anonymous

ok thanks for you help!

- xapproachesinfinity

:)

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