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anonymous
 one year ago
Apply the distributive formula to
(x+y)^2 = x^2 + 2xy + y^2
anonymous
 one year ago
Apply the distributive formula to (x+y)^2 = x^2 + 2xy + y^2

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xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1first do this \((x+y)^2=(x+y)(x+y)\)

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.1now try to distribute

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439924847191:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(x+y) (x+y) = (x^2 + xy + xy + y^2) @xapproachesinfinity @Crazyandbeautiful

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0combine like terms, you have the right hand side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i just combine all thats on the left now?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Crazyandbeautiful x^2+xy+xy+y^2 = (x^2 + xy + xy + y^2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Crazyandbeautiful @xapproachesinfinity is this right???

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[xy+xy=2xy\] Just like how \[a+a=2a\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you understand that @The_Yee_Dinosaur

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but it is not a true equation now such as 25=25 or 17=17 right? @Crazyandbeautiful

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It is true, an equation is what an equation is, the left side is equal to the right side try it for your self take an example \[(3+4)^2\] Let's solve it directly and using the identity Directly first \[(3+4)^2=7^2=49\] Now we apply the identity \[(3+4)^2=3^2+4^2+2(3)(4)=9+16+24=49\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Think of it like this, x and y are numbers so if you multiply x and y, that is calculate \[xy\](the product of x and y) you will get another number) now suppose you add that same final number you got that itself what do you get? It's 2 times the number itself Math will work whether you take letters or numbers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Suppose x=3 and y=4 \[xy=3\times4=12\] \[12+12=24=2 \times 12\] \[xy+xy=2xy=2 \times xy\]

phi
 one year ago
Best ResponseYou've already chosen the best response.0they may want you do use the distributive property twice \[ (x+y)(x+y) \] if we call the first (x+y) "A" (to make it clearer) we would do this (distribute) \[ A (x+y) = Ax + Ay \] and A is really (x+y), so this is \[ (x+y)(x+y)=(x+y)x + (x+y)y \] now distribute again. in other words the first (x+y)x becomes x^2 +xy and the second term becomes xy+y^2 \[ (x+y)x + (x+y)y = x^2 +xy+xy+y^2 \] finally , add xy+xy (1 xy plus another xy is 2xy) \[ (x+y)(x+y)= x62+2xy+y^2 \]
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