anonymous
  • anonymous
HELP PLEASE DON'T GET IT A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% of the time. When she misses the first shot, she misses the second shot 5% of the time. What is the probability of missing both free-throw shots?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@phi please help me
phi
  • phi
you multiply the probability of missing the first times prob of missing the 2nd what is the prob of missing the first?
anonymous
  • anonymous
40%

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

phi
  • phi
yes, or 0.4 what is the prob of missing the 2nd? (and we have to assume we missed the first, because we are looking for the prob of missing both)
anonymous
  • anonymous
5% or 0.05
phi
  • phi
now multiply 0.4*0.05
anonymous
  • anonymous
you get 0.02 or 2%
phi
  • phi
yes
anonymous
  • anonymous
so that is the answer 2%
phi
  • phi
yes
anonymous
  • anonymous
thank for helping me

Looking for something else?

Not the answer you are looking for? Search for more explanations.