How many grams of Sodium hydroxide are present in 50.0 mL of a Sodium hydroxide solution that is 0.0950 M?
moles solute = molarity x L of solution
50ml = 0.05 L
0.0950 M * 0.05 L = 0.0475 moles solute
0.0475 moles solute * 39.99711 g OH = 1.90 g OH
Is this correct @cuanchi ?
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they give you (molarity) and the volume of NaOH and ask for the number of grams but she says that the procedure she did was wrong,
When I type it into my calculator for that first part the 0.0950x0.05 I get 0.00475 not 0.0475 so that would give a final answer of 0.1899g
Tara I assumed that her numbers were correct, I was just checking like how she did the set up
Ya I saw the set up was fine so I questioned the calculations simple error
Did you get what tara explained?
However, all given non-exact information is given to 3 significant figures, so the answer should be 0.190 g as opposed to 0.19 g.
The number of significant figures in Chemistry is of utmost importance.