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Lena772

  • one year ago

How many grams of Sodium hydroxide are present in 50.0 mL of a Sodium hydroxide solution that is 0.0950 M? moles solute = molarity x L of solution 50ml = 0.05 L 0.0950 M * 0.05 L = 0.0475 moles solute 0.0475 moles solute * 39.99711 g OH = 1.90 g OH Is this correct @cuanchi ?

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  1. Lena772
    • one year ago
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    @mathmate

  2. Photon336
    • one year ago
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    \[liters*\frac{ mol }{ L } = moles \] \[moles solute NaOH* \frac{ mass NaOH }{ 1 mol }\]

  3. Photon336
    • one year ago
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    That was supposed to be molar mass of NaOH, that's just to illustrate how the units cancel out, and that's why it's important to include them in your calculation.

  4. Lena772
    • one year ago
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    @Photon336 I submitted and it says it's incorrect.

  5. Photon336
    • one year ago
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    @taramgrant0543664

  6. Photon336
    • one year ago
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    they give you (molarity) and the volume of NaOH and ask for the number of grams but she says that the procedure she did was wrong,

  7. taramgrant0543664
    • one year ago
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    When I type it into my calculator for that first part the 0.0950x0.05 I get 0.00475 not 0.0475 so that would give a final answer of 0.1899g

  8. Photon336
    • one year ago
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    Tara I assumed that her numbers were correct, I was just checking like how she did the set up

  9. taramgrant0543664
    • one year ago
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    Ya I saw the set up was fine so I questioned the calculations simple error

  10. mathmate
    • one year ago
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    @lena772 Did you get what tara explained? However, all given non-exact information is given to 3 significant figures, so the answer should be 0.190 g as opposed to 0.19 g. The number of significant figures in Chemistry is of utmost importance.

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