anonymous
  • anonymous
A ball is dropped from a tower 550 meters above the ground with position function s(t) = 4.9t2+ 550. What is the velocity of the ball after 3 seconds What is the velocity of the ball after 3 seconds
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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dan815
  • dan815
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dan815
  • dan815
did u mean to ask what is the distance after 3 seconds because right now its asking the same question twice
anonymous
  • anonymous
no just velocity. that second one was an accident

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dan815
  • dan815
remember that velocity = change in displacement / time
dan815
  • dan815
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dan815
  • dan815
derivative of a function tells you the slope of that function wrt to time everywhere
anonymous
  • anonymous
yeah I just get confused with what comes after S(t)
dan815
  • dan815
okay i see
dan815
  • dan815
you know that gravity is 9.8m/s^2 right
anonymous
  • anonymous
yeah
dan815
  • dan815
if u look carefully this equation models that
dan815
  • dan815
if u differentiate twice s'(t)=2*4.9*t s''(t) = 2*4.9=9.8
dan815
  • dan815
accerlation is the 2nd derivative of s(t) function
dan815
  • dan815
acceleration is how velocity change wrt to time so its the slope of the velocity function velocity is how displamenet changes wrt to time so its the slope of the distance function
dan815
  • dan815
the units also tell you for example 9.8 m/s^2 = 9.8 m/s /s the units m/s /s
dan815
  • dan815
change in speed or velocity / second
dan815
  • dan815
just one thing i think is a bit akward here is that they didnt put a - sign infront of your equation
dan815
  • dan815
so i guess position velocity in your case really means downward towards earth
dan815
  • dan815
positive*
anonymous
  • anonymous
yeah I noticed that to but I figured it was a typo or something

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