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jchick
 one year ago
solve and show all work for a2 – a – 20 and a2 – 5a – 20
jchick
 one year ago
solve and show all work for a2 – a – 20 and a2 – 5a – 20

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myininaya
 one year ago
Best ResponseYou've already chosen the best response.1what are you solving?

jchick
 one year ago
Best ResponseYou've already chosen the best response.0Factor each trinomial below. Please show your work and check your answer.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1ok for the first one we have a^2a20 a^21a20 so first step is to ask yourself what two integers multiply to by 20 and add up to be 1?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1\[ax^2+bx+c \\ \text{ when } a=1 \text{ and if the expression is "factorable" } \\ \text{ then you should be able to find } \\ \text{ two integers so that when you multiply them together you get } c \\ \text{ and when you add them together you get } b\] for example: \[x^2+5x+6 \\ \text{ the question here first to answer is: } \\ \text{ what two integers multiply to be 6 } \\ \text{ and add up to be 5}\] well 2(3)=6 and 2+3=5 so the factored form of \[x^2+5x+6 \text{ is } (x+2)(x+3)\]

jchick
 one year ago
Best ResponseYou've already chosen the best response.0a2 – a – 20 (a )(a ) 4*5 10*2 (a+4)(a5) a2 5a+4a2 a a2 – 5a – 20 (a )(a ) 10*2 5*4 (a5)(a+4) a2 + 12ab + 27b2 (a )(a ) 9*3 (a+3b)(a+9b) a2 +9ab+3ab+27b a2 +12ab+27b

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1yes to the first one: a^2a20=(a5)(a+4) since 5*4=20 and 5+4=1 no to the second one: a^25a20 this does not equal (a5)(a+4) 5(4)=20 but 5+4 isn't 5

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1and the third one looks good

jchick
 one year ago
Best ResponseYou've already chosen the best response.0a2 – a – 20 (a )(a ) 4*5 10*2 (a+4)(a5)

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1so you got 2/3 correct

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1you just need to fix the second one

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1a^25a20 are there two integers that multiply to be 20 and add up to be 5?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1possible pairings that multiply to be 20: 1(20) 1(20) 2(10) 2(10) 4(5) 4(5)

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1do any of those pairs also add up to 5?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1which equation is true if any: 1+(20)=5 1+20=5 2+(10)=5 2+10=5 4+(5)=5 4+5=5

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1so that means that this is a prime trinomial

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1means it is not "factorable"

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1I put factorable in quotation marks because it only really means it isn't factorable over the integers

jchick
 one year ago
Best ResponseYou've already chosen the best response.0So I am not sure on the second one

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1a^25a20 does not factor

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1unless you can factor over the reals?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1which I don't think that is the instructions

jchick
 one year ago
Best ResponseYou've already chosen the best response.0No but how would I write this just say it is prime?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1you can either say not factorable or prime

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1which ever vocabulary your teacher prefers really but either saying is fine in general

jchick
 one year ago
Best ResponseYou've already chosen the best response.0Part 1: Factor each trinomial below. Please show your work and check your answer. For the first one: x^2  8 x + 15 x^2  5x  3x + 15 x(x5) 3(x5) (x5)(x3) The check: x(x3)5(x3) x^2 – 3x5x+15 x^28x+15 Question 2: a2 – 5a – 20 Prime and cannot be factored. Question: 3 a^2  a  20 a^2 5a+4a20 a(a5)+4(a5) (a5)(a+4) Question 4: a^2 + 12ab + 27b^2 a^2 + 9ab + 3ab + 27b^2 a(a+9b) + 3b(a+9b) (a+9b)(a+3b) Question 5: 2a2 + 30a + 100 2(a^2 + 15a + 50) the values that add to give 15a multiply to 50a^2 are 10a and 5a 2(a^2 + 5a + 10a + 50) 2[a(a+5) +10(a+5)] 2(a+5)(a+10) Question 6: Part 2: (5 points) It’s your turn to be a game show host! As you know, in the game of Math Time, the contestants are given an answer and they must come up with the question that corresponds to the given answer. Your task for this portion of the assignment is to create two different “answers” (and the questions that accompany them) that the host could use for the final round of Math Time. The questions and answers you create must be unique. Check out the example and hint below, if needed. 1 point for creating the two questions and answers. 2 points per question/answer for accuracy. Example: Question for Host: x2 + 6x + 5 is the product of these two binomials. Expected Question from Contestant: What is (x + 5)(x + 1)? HINT: Create the two binomials first and then use the distribution method to find their simplified product. The simplified product is the answer and the two binomial factors, the expected question. Hosts question 1: The product of these two binomials is x2+x20 Answer: What is (x+5)(x4) Hosts question 2: The product of these two binomials is x2+7xy+12y Answer: What is (x+3y)(x+4y)
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