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anonymous

  • one year ago

WILL GIVE MEDAL PLEASE HELP! The graph of f(x) = 2x + 1 is shown below. Explain how to find the average rate of change between x = 0 and x = 3.

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @Hero @myininaya

  3. zepdrix
    • one year ago
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    The average rate of change from x=0 to x=3 is going to be the slope of the line from x=0 to x=3. So we need to find slope :) Remember your slope formula? \(\large\rm \frac{y_2-y_1}{x_2-x_1}\) We find out how much the y (height) changed, divide it by the x change, and that gives us slope, rise over run. Our x1 and x2 are clearly x=0 and x=3. What about y2? Maybe it's easier if I write the slope formula using function notation :) Relates better to this problem I guess.

  4. zepdrix
    • one year ago
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    slope:\(\large\rm \frac{f(x_2)-f(x_1)}{x_2-x_1}\) We know our x's: \(\large\rm \frac{f(3)-f(0)}{3-0}\) So for our y's, we need to know what the function is equal to when x=0 and when x=3. So what do you get for f(3)? \[\large\rm f(\color{orangered}{x})=2^{\color{orangered}{x}}+1\]\[\large\rm f(\color{orangered}{3})=2^{\color{orangered}{3}}+1\]What does that simplify to? :)

  5. anonymous
    • one year ago
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    F= 9

  6. zepdrix
    • one year ago
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    Good good good.\[\large\rm f(\color{orangered}{x})=2^{\color{orangered}{x}}+1\]\[\large\rm f(\color{orangered}{0})=2^{\color{orangered}{0}}+1\]How bout the other one?

  7. anonymous
    • one year ago
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    F= 2

  8. zepdrix
    • one year ago
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    \[\large\rm m=\frac{9-2}{3-0}\]Cool! Now find your slope! :D

  9. anonymous
    • one year ago
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    7/3 ?

  10. zepdrix
    • one year ago
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    Good good good. The function went up by 7, over a distance of 3. So an average rate of change of 7/3. Yayyyy good job \c:/

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