cocoapeebles3
  • cocoapeebles3
Xavier is riding on a Ferris wheel at the local fair. His height can be modeled by the equation H(t) = 20cosine of the quantity 1 over 15 times t + 30, where H represents the height of the person above the ground in feet at t seconds. Part 1: How far above the ground is Xavier before the ride begins? Part 2: How long does the Ferris wheel take to make one complete revolution? Part 3: Assuming Xavier begins the ride at the top, how far from the ground is the edge of the Ferris wheel, when Xavier's height above the ground reaches a minimum?
Mathematics
chestercat
  • chestercat
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cocoapeebles3
  • cocoapeebles3
-.- I just needed help figuring it out I have been stuck on it for hours and I thought openstudy would help but obviously not @IrishBoy123
cocoapeebles3
  • cocoapeebles3
Okay for part 1 i think you just have to substitute in 0 for t. H(0)= 20cos(pi/15(o))+30 which is 50. But I'm not sure if that's right.
IrishBoy123
  • IrishBoy123
why not just draw the equation? i can guess sorta what you are trying to do, but that really defeats the point. loads of people here want to help and learn.

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IrishBoy123
  • IrishBoy123
|dw:1439938025351:dw|
IrishBoy123
  • IrishBoy123
|dw:1439938102822:dw|
IrishBoy123
  • IrishBoy123
or post a url or do a screengrab or scribble it down and scan and link it
IrishBoy123
  • IrishBoy123
|dw:1439938283787:dw|
IrishBoy123
  • IrishBoy123
i am sorry to be such a pain but, once you get this bit sorted, you will get loads of help!
cocoapeebles3
  • cocoapeebles3
|dw:1439938250052:dw|
IrishBoy123
  • IrishBoy123
an example of posting a screengrab https://gyazo.com/9bd2129de27eaf26d56f85c2ffee15eb
cocoapeebles3
  • cocoapeebles3
sorry I'm new to this
IrishBoy123
  • IrishBoy123
we all were once please stick with it your drawing is off the screen for me https://gyazo.com/944f3bbd967745366c90fa0c079f5f56
IrishBoy123
  • IrishBoy123
|dw:1439938633443:dw|
cocoapeebles3
  • cocoapeebles3
cocoapeebles3
  • cocoapeebles3
which I think is equal to 50
IrishBoy123
  • IrishBoy123
and where is the \(\pi \) being brought in? it is not in the original post...
IrishBoy123
  • IrishBoy123
\(\pi\) https://gyazo.com/ca2e80c981ef716a06b30d2fe7207627
IrishBoy123
  • IrishBoy123
strongly suggest you close this and start a new thread with the same question i am pretty easy going but this is too much, even for me. having learned something about how to share info online, you will have better luck with a new thread, the audience will have less to guess. good luck, and wish you well!
cocoapeebles3
  • cocoapeebles3
oh sorry the original equation is this\[H(t)= 20\cos(\pi/15\times t) + 30\]
cocoapeebles3
  • cocoapeebles3
okay thanks
IrishBoy123
  • IrishBoy123
thanks for that @cocoapeebles3 if this is right, \(\large H(t)=20cos(\frac{π t}{15})+30\) then as cos(0) = 1 you have \(h(0) = 20+30=50\) the *period* of the wheel can be got from \(\omega \ t = \frac{π }{15}t= \frac{2 \pi}{T} t \) \(\frac{π }{15}t= \frac{2 \pi}{T} t \implies T = 30 \) finally, \(10 \le h(t) \le 50\) simply because \(-1 \le cos \le 1\)
IrishBoy123
  • IrishBoy123
there might be a load of jargon in there so please do persist if anything is unclear and you have to factor in errors on my part too cheers!
cocoapeebles3
  • cocoapeebles3
I think I understand it all thank you so much!
cocoapeebles3
  • cocoapeebles3
So for part 3 how would I word that?
IrishBoy123
  • IrishBoy123
for last part \(H = \pm 20 + 30\) because cosine goes from -1 to +1.

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