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anonymous
 one year ago
What is the missing exponent?
anonymous
 one year ago
What is the missing exponent?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, we still work in the correct order of operations. In other words, let's work with the denominator first.\[\left(8^{7}\right)^2 = 8^{7}\times8^{7}\]Here, you are multiplying, so what should that simplify to? (aka \(8^{??}\))

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When you multiply, you add the exponents. You would get \(8^0\) if you subtracted them.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes. So, plugging that in again, \[\frac{8^{5}}{8^{14}} = 8^{?}\] We are dividing here.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(im putting my baby bro. to sleep right now so i might type slow i only have 1 hand)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(That's fine.) You're dividing in general, so you're going to have to either add or subtract the exponents. When you multiply, you added, so when you divide, you...?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes! Also, just in general, the only time you will multiply exponents (with the same bases, like here where you had 8 on the bottom) is when you have something like \(\left(8^3\right)^2\). This would simplify to \(8^6\) because what you're doing is \(8^3 \times8^3\).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok tysm! You're so smart :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, for you to write down, you can say \(\left(a^b\right)^c = a^{bc}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I GOT A 100!!!!!!!!!!
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