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anonymous

  • one year ago

What is the missing exponent?

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    Ok, we still work in the correct order of operations. In other words, let's work with the denominator first.\[\left(8^{-7}\right)^2 = 8^{-7}\times8^{-7}\]Here, you are multiplying, so what should that simplify to? (aka \(8^{??}\))

  3. anonymous
    • one year ago
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    8^0???

  4. anonymous
    • one year ago
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    When you multiply, you add the exponents. You would get \(8^0\) if you subtracted them.

  5. anonymous
    • one year ago
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    oh ok so its 8^-14

  6. anonymous
    • one year ago
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    Yes. So, plugging that in again, \[\frac{8^{-5}}{8^{-14}} = 8^{?}\] We are dividing here.

  7. anonymous
    • one year ago
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    dividing which ones

  8. anonymous
    • one year ago
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    (im putting my baby bro. to sleep right now so i might type slow i only have 1 hand)

  9. anonymous
    • one year ago
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    1 hand free*

  10. anonymous
    • one year ago
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    (That's fine.) You're dividing in general, so you're going to have to either add or subtract the exponents. When you multiply, you added, so when you divide, you...?

  11. anonymous
    • one year ago
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    subtract

  12. anonymous
    • one year ago
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    so 8^9

  13. anonymous
    • one year ago
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    9 is the answer?

  14. anonymous
    • one year ago
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    Yes! Also, just in general, the only time you will multiply exponents (with the same bases, like here where you had 8 on the bottom) is when you have something like \(\left(8^3\right)^2\). This would simplify to \(8^6\) because what you're doing is \(8^3 \times8^3\).

  15. anonymous
    • one year ago
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    ok tysm! You're so smart :D

  16. anonymous
    • one year ago
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    So, for you to write down, you can say \(\left(a^b\right)^c = a^{bc}\)

  17. anonymous
    • one year ago
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    i did

  18. anonymous
    • one year ago
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    I GOT A 100!!!!!!!!!!

  19. anonymous
    • one year ago
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    Good job!! :)

  20. anonymous
    • one year ago
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    tysm!!! i gtg bye

  21. anonymous
    • one year ago
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    np

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