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brodybarnes35

  • one year ago

Which of the following represents the factored form of f(x) = x^3 − 64x? f(x) = x(x + 8)(x − 8) f(x) = (x − 8)(x + 8) f(x) = x(x − 8)^2 f(x) = x(x^2 − 8)

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  1. brodybarnes35
    • one year ago
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    @Hero

  2. brodybarnes35
    • one year ago
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    FAN AND MEDAL

  3. brodybarnes35
    • one year ago
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    idk :/ thats embarrassing wow

  4. brodybarnes35
    • one year ago
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    but really idk could you explain

  5. brodybarnes35
    • one year ago
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    ohhhh im so stupid sorry X

  6. brodybarnes35
    • one year ago
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    -64 = x? what

  7. brodybarnes35
    • one year ago
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    9 and 7

  8. brodybarnes35
    • one year ago
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    no thats 63 my b

  9. brodybarnes35
    • one year ago
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    OMG WTH IM DUMB

  10. brodybarnes35
    • one year ago
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    8*8 UGHHH

  11. brodybarnes35
    • one year ago
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    -8 * 8

  12. brodybarnes35
    • one year ago
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    ???

  13. Hero
    • one year ago
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    @brodybarnes35, what happens to the expression after you factor out the x?

  14. brodybarnes35
    • one year ago
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    so its either a or b right

  15. brodybarnes35
    • one year ago
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    idk @hero

  16. brodybarnes35
    • one year ago
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    a or b right @mehek14 @hero ?

  17. brodybarnes35
    • one year ago
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    @Mehek14 ???

  18. brodybarnes35
    • one year ago
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    o ok :/

  19. brodybarnes35
    • one year ago
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    @Nnesha can you help?

  20. Nnesha
    • one year ago
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    first find GCF(greatest common factor ) so there is x common in both terms right ? now take out the x from x^3 and -64x or in other words divide both terms by common factor \[\rm x^3-64x=x(???-???)\]

  21. Nnesha
    • one year ago
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    |dw:1439937064914:dw| divide both terms by common factor and write your answer in the parentheses.

  22. brodybarnes35
    • one year ago
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    if you divide by x the outcome would be the same?

  23. brodybarnes35
    • one year ago
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    @Nnesha

  24. Nnesha
    • one year ago
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    not yet.there is one more step. just divide x^3 by x and then -64x by x

  25. Nnesha
    • one year ago
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    x^3/x= ?? -64x/x= ?

  26. brodybarnes35
    • one year ago
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    = x^3 =-64x the outcome is the same when you divide...or am i doing it wrong

  27. brodybarnes35
    • one year ago
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    wait does the x disappear?

  28. Nnesha
    • one year ago
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    i don't get it. what do you mean? x^3 over x isn't equal to x^3

  29. Nnesha
    • one year ago
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    x^3 is same as x times x times x \[\huge\rm \frac{ x \times x \times x }{ x }\]can you divide now?

  30. brodybarnes35
    • one year ago
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    its 1x or x?

  31. Nnesha
    • one year ago
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    x^3 is same as x times x times x \[\huge\rm \frac{ x \times x \times \cancel{x} }{\cancel{ x }}\]how many x's wre there ?

  32. brodybarnes35
    • one year ago
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    2x? now

  33. Nnesha
    • one year ago
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    x^3 is same as x times x times x \[\huge\rm \frac{\color{Red}{ x} \times\color{Red}{ x} \times \cancel{\color{Red}{x}} }{\cancel{ x }}\]how many x's wre there ?

  34. brodybarnes35
    • one year ago
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    2x

  35. Nnesha
    • one year ago
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    no when you multiply same bases you should add their exponents \[\huge\rm x^m \times x^n = x^{m+n}\] when you ADD same bases then you should add their coefficient 1x+1x=(1+1))x=2x

  36. Nnesha
    • one year ago
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    and x is same as x to the one power \[\rm x^1 \times x^1 =x^{??}\]

  37. brodybarnes35
    • one year ago
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    x^2

  38. Nnesha
    • one year ago
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    right so x^3 over x = x^2|dw:1439937679559:dw| now divide -64x over x ?

  39. Hero
    • one year ago
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    Another way to understand factoring is to think of it in terms of the distributive property. ab + ac = a(b + c) In other words, a is common to both terms on the left so we factor it out to get the expression on the right.

  40. brodybarnes35
    • one year ago
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    ummm that would be -64x^2?

  41. Nnesha
    • one year ago
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    \[\frac{ -64x }{ x} = ?\] here you have to divide by x what would get when you divide same bases ? like 2/2 = ?

  42. brodybarnes35
    • one year ago
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    2/2 = 1 right so -64x would be -64x?

  43. Nnesha
    • one year ago
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    you are right. -64x would be -64x but what is \[\huge\rm \frac{ -64\color{Red}{x} }{ \color{Red}{x} } = ?\]

  44. brodybarnes35
    • one year ago
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    x^1????

  45. Nnesha
    • one year ago
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    Take out x from -64x. that's it.

  46. brodybarnes35
    • one year ago
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    omg wow that was simple -.- im dumb

  47. Nnesha
    • one year ago
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    so when you take out x from -64x what will u have left with ?

  48. brodybarnes35
    • one year ago
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    -64?

  49. Nnesha
    • one year ago
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    right!!

  50. brodybarnes35
    • one year ago
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    ok so what happens now lol?

  51. Nnesha
    • one year ago
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    |dw:1439938027333:dw| \[\huge\rm x(x^2-64)\] now apply the difference of square method \[\huge\rm a^2-b^2=(a+b)(a-b)\]

  52. Nnesha
    • one year ago
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    \[\huge\rm x(\color{red}{x^2-64})\] now apply the difference of square method \[\huge\rm a^2-b^2=(a+b)(a-b)\] take square of both terms in the parentheses write ur answer as (sqrt of 1st term + sqrt of 2nd term)(sqrt of 1st term - sqrt of 2nd term )

  53. brodybarnes35
    • one year ago
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    x^3 - 64x

  54. Nnesha
    • one year ago
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    that's the original equation what about it ?

  55. brodybarnes35
    • one year ago
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    oh nvm

  56. brodybarnes35
    • one year ago
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    what a and what is b

  57. Nnesha
    • one year ago
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    a and b are variables a = first term b= 2nd term

  58. brodybarnes35
    • one year ago
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    yeah but what are they like number wise..

  59. Nnesha
    • one year ago
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    |dw:1439938335253:dw|

  60. brodybarnes35
    • one year ago
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    x^2 - 64^2 = ( x2 + 64) ( x2 - 64)?

  61. Nnesha
    • one year ago
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    no take square root of both terms look at the equation i gave you it's not \[\huge\rm a^2-b^2\cancel{=}(a^2-b^2)(a^2+b^2)\]

  62. brodybarnes35
    • one year ago
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    B

  63. Nnesha
    • one year ago
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    how did you get b? what about common that's outside the parentheses?

  64. Nnesha
    • one year ago
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    common factor*

  65. brodybarnes35
    • one year ago
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    because just they look alike ( - )( + ) the signs match... am i right

  66. Nnesha
    • one year ago
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    |dw:1439938542139:dw| take square root of both terms write your answer in the parentheses

  67. brodybarnes35
    • one year ago
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    it is B!!

  68. anonymous
    • one year ago
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    its A x(x-8)(x+8)

  69. Nnesha
    • one year ago
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    don't look at the answer choices

  70. brodybarnes35
    • one year ago
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    oh its a yikes

  71. Nnesha
    • one year ago
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    why it's a ?

  72. brodybarnes35
    • one year ago
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    she said it

  73. Nnesha
    • one year ago
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    she is not gonna be there when you have to take final exam.

  74. brodybarnes35
    • one year ago
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    (x - 8)(x + 8) right?

  75. anonymous
    • one year ago
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    x(x^2-64)= x^3-64x

  76. Nnesha
    • one year ago
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    that should go in the parentheses|dw:1439938908541:dw| common should stay there outside the parentheses.

  77. brodybarnes35
    • one year ago
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    ohhhh so A

  78. brodybarnes35
    • one year ago
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    @Nnesha

  79. anonymous
    • one year ago
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    yes

  80. Nnesha
    • one year ago
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    yes|dw:1439938990977:dw|

  81. brodybarnes35
    • one year ago
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    ok thanks can you help with one more?

  82. brodybarnes35
    • one year ago
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    please

  83. brodybarnes35
    • one year ago
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    ???

  84. Nnesha
    • one year ago
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    @ana123456 don't give out direct answer especially when someone spnd one HOUR to teach.

  85. Nnesha
    • one year ago
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    and sorry i have to go :) good luck!!

  86. brodybarnes35
    • one year ago
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    ok

  87. brodybarnes35
    • one year ago
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    ana can you help lol

  88. brodybarnes35
    • one year ago
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    @ana123456

  89. brodybarnes35
    • one year ago
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    one more question pls

  90. anonymous
    • one year ago
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    sure

  91. brodybarnes35
    • one year ago
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    nvm i got it thanks

  92. anonymous
    • one year ago
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    you're welcome

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