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The axis of symmetry is the vertical line that goes through the vertex of a quadratic equation.

I understand how to get it from a graph just not in vertex or standard equation form

y=3(x+4)2+1

That is the vertex form

(−4,1) is the vertex

oh okay, I hforget that the h spot hould be a -

The standard form of a parabola's equation is generally expressed:
y=ax2+bx+c

The vertex form of a parabola's equation is generally expressed as: y = a(x-h)^2+k

uh huh, and the axis is normally x=-b/2 a right ? for standard?>

Do you mean The axis of symmetry?

yes

ok

Axis of Symmetry from Standard Form ax^2 + bx + c

a(x - h)^2 + k is vertex form

The first one is the standard form

Axis of Symmetry in Standard Form ax^2 + bx + c

yeah. so what gets the axis from standard?

wait I thought that the standard form equation was ax^2+bx+C not the axis of symmetry .....

|dw:1439938305007:dw|

???

that is the axis of symmetry

-5/2a? what that from??

That is -b on top

sorry bad drawing

Do you understand now?

|dw:1439938524109:dw|

that's okay. so if I had 2x^2-16x+15 the axis of symmetry would be 16/2(2) so itd be 4?

Yes

oh okay now I get it

Ok good I didn't mean to be confusing.

its okay

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Do you have anymore questions

I did fan you on the last ? and idk yet I might.. ill tag you in the though..

Ok I didn't see it sorry lol

Ok