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The axis of symmetry is the vertical line that goes through the vertex of a quadratic equation.
@jchick can you help with this too? since its in vertex form would it be (4,1)?
I understand how to get it from a graph just not in vertex or standard equation form
That is the vertex form
(−4,1) is the vertex
oh okay, I hforget that the h spot hould be a -
The standard form of a parabola's equation is generally expressed: y=ax2+bx+c
The vertex form of a parabola's equation is generally expressed as: y = a(x-h)^2+k
If a is positive then the parabola opens upwards like a regular "U". If a is negative, then the graph opens downwards like an upside down "U".
uh huh, and the axis is normally x=-b/2 a right ? for standard?>
Do you mean The axis of symmetry?
Axis of Symmetry from Standard Form ax^2 + bx + c
I get the vertex form now and what changes the direction a parabola open just not how to get the axis of symmetry in standard form.
a(x - h)^2 + k is vertex form
The first one is the standard form
Axis of Symmetry in Standard Form ax^2 + bx + c
yeah. so what gets the axis from standard?
The standard form of a parabola's equation is generally expressed: y=ax2+bx+c The role of 'a' If a>0, the parabola opens upwards if a<0 it opens downwards.
wait I thought that the standard form equation was ax^2+bx+C not the axis of symmetry .....
that is the axis of symmetry
-5/2a? what that from??
That is -b on top
sorry bad drawing
Do you understand now?
that's okay. so if I had 2x^2-16x+15 the axis of symmetry would be 16/2(2) so itd be 4?
oh okay now I get it
Ok good I didn't mean to be confusing.
Don't forget to fan me and also to give a medal for answers
If you fan me it is easier for me to find your future questions
Do you have anymore questions
I did fan you on the last ? and idk yet I might.. ill tag you in the though..
Ok I didn't see it sorry lol