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Teddyiswatshecallsme
 one year ago
NEED HELP! Conics  Circles
Write the general conic form equation of each circle.
1. (x + 3)^2 + (y + 6)^2 = 81
2. (x + 6)^2 + (y  2) = 64
3. (x + 14)^2 + y^2 = 24
Teddyiswatshecallsme
 one year ago
NEED HELP! Conics  Circles Write the general conic form equation of each circle. 1. (x + 3)^2 + (y + 6)^2 = 81 2. (x + 6)^2 + (y  2) = 64 3. (x + 14)^2 + y^2 = 24

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Teddyiswatshecallsme
 one year ago
Best ResponseYou've already chosen the best response.0Please provide a thorough explanation of how you're doing them. I need to understand this stuff.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf (x{\color{brown}{ h}})^2+(y{\color{blue}{ k}})^2={\color{purple}{ r}}^2 \qquad center\ ({\color{brown}{ h}},{\color{blue}{ k}})\qquad radius={\color{purple}{ r}} \\ \quad \\ \quad \\ hint:\qquad (x {\color{brown}{ +3}})^2 + (y {\color{blue}{ +6}})^2 = {\color{purple}{ 81}}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm kinda misread.. the genercal conic hmmm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hint: divide the left side, by the right side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf (x + 3)^2 + (y + 6)^2 = 81 \implies \cfrac{(x + 3)^2}{81} + \cfrac{(y + 6)^2}{81} = \cfrac{\cancel{81}}{\cancel{81}} \\ \quad \\ \textit{keeping in mind } \\ \quad \\ \cfrac{(x{\color{brown}{ h}})^2}{{\color{purple}{ a}}^2}+\cfrac{(y{\color{blue}{ k}})^2}{{\color{purple}{ b}}^2}=1 \qquad center\ ({\color{brown}{ h}},{\color{blue}{ k}})\qquad vertices\ ({\color{brown}{ h}}\pm a, {\color{blue}{ k}}) \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0also keep in mind that +3 =  (3)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0@jdoe0001 I think they want to expand everything out? For example, (x + 3)^2 = x^2 + 6x + 9

Teddyiswatshecallsme
 one year ago
Best ResponseYou've already chosen the best response.0Now what?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Dat sit!! They ask you to get the conic form, just divide both side by the right hand side and you get the conic form of a circle.

Teddyiswatshecallsme
 one year ago
Best ResponseYou've already chosen the best response.0I'm not getting it. o.o

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0To get more details, you can say that that is the "ellipse" with vertices are (\(0,\pm 9\) ) and (\(\pm9, 0)\) Foci (0,0)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 hmmm methinks is the conic version of it, rather than an expanded one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Why not? Like parabola, you have 2 different forms: Standard form and vertex form. Same as circle.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jdoe0001 you are invisible to me again. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0anyhow @Teddyiswatshecallsme there, make it like an ellipse equation keep in mind that +3 = (3) and that +6 = (6)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry, parabola has 3 forms, polar form also. :)
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