Interval notation of this problem: Find the domain of the function: b) g(x)= 1/(x^2-x) I know that x can't equal to 1 or 0, but I can't figure out how write the notation.

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Interval notation of this problem: Find the domain of the function: b) g(x)= 1/(x^2-x) I know that x can't equal to 1 or 0, but I can't figure out how write the notation.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Do you know how to find the domain?
Yup! You set the bottom part of the fraction equal to zero right?
Ok so what is the domain?

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Other answers:

In "Interval Notation" we just write the beginning and ending numbers of the interval, and use: [ ] a square bracket when we want to include the end value, or ( ) a round bracket when we don't
Interval notation has to do with graphing can you graph this?
So can you find the interval notation of this one?
Which side is open?
hmmm... it would equal x<0 or x>10 or 0
Ok so if the side with the zero is open it is represented with a ( right?
oh the zero would be open and the 10 is closed
And if the side with the ten is closed than it would be represented with a ] right?
Well you tell me which one is it?
(0,10]
Yes the zero is open and the ten is closed so what is the notation
Correct!!
Ok so do you know how to graph your question?
yup I think i got it but just in case, I'll send you a picture of how i graphed it later to make sure I did it right
Ok
So did you get a solution?

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