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anonymous
 one year ago
HELP!!! I WILL DO ANYTHING
anonymous
 one year ago
HELP!!! I WILL DO ANYTHING

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The function H(t) = 16t2 + vt + s shows the height H (t), in feet, of a projectile launched vertically from s feet above the ground after t seconds. The initial speed of the projectile is v feet per second. Part A: The projectile was launched from a height of 82 feet with an initial velocity of 60 feet per second. Create an equation to find the time taken by the projectile to fall on the ground. (2 points) Part B: What is the maximum height that the projectile will reach? Show your work. (2 points) Part C: Another object moves in the air along the path of g(t) = 10 + 63.8t where g(t) is the height, in feet, of the object from the ground at time t seconds. Use a table to find the approximate solution to the equation H(t) = g(t), and explain what the solution represents in the context of the problem? [Use the function H(t) obtained in Part A, and estimate using integer values] (4 points) Part D: Do H(t) and g(t) intersect when the projectile is going up or down, and how do you know? (2 points)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0YEAH, I have that part. but what do you mean by A;0 .. I have the numbers plugged in .. just solving is difficult

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0A: 0. Sry. Forgot the space

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0Just sayin for problem a.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0either way what do you mean??

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0The equation for problem a is 0=16t2+60t+82

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4part A is definitely 0 = 16t^2+60t+82. So you have the correct answer there for that part. initial velocity = 60 ft/s v = 60 initial height = 82 ft s = 82

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4for part b, consider the equation y = 16x^2+60x+82 it is in the form y = ax^2 + bx + c

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay... now what do i do?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4notice how a = 16, b = 60, c = 82 plug the values of a and b into h = b/(2a) and tell me what you get for h

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4it should be positive

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4you lost a sign somewhere

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea. it is . i accidentally put it there

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4now plug x = 1.875 into y = 16x^2+60x+82 to get the value of y what is the value of y?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4that's too big

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0,,,,, but i plugged the number in and I'm sure i solved it correctly..

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.416x^2+60x+82 16(1.875)^2+60(1.875)+82 ... replace every x with 1.875 now compute `16(1.875)^2+60(1.875)+82`

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah.. thats what i had. .let me retry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay great.. next step?

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0For c, u make the equation in a equal 10 +63.8t 10+63.8t=16t2+60t+82 In which you solve for t, then plug it in in one of the equations

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4So when the time is t = 1.875 seconds, the height of the object is 138.25 ft which is the peak height dw:1439942710928:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4dw:1439942749753:dw

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0I thought u were done with b, sry for interupting😰

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4what kind of calculator do you have?

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0So basically, 138.25 meters is the answer to b

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Texas Instruments TI 30X

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4have you used a website called desmos before? It's a free graphing calculator

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4yes @Plasmataco

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4ok we're going to use that to answer part c

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok what do i type in?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4type in f(x) = 16x^2 + 60x + 82 into the first box and g(x) = 10 + 63.8x into the second box let me know when you have that in and I'll move onto the next step

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0You want go and fx to be the same

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0Gx dang it autocorrect

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay done.. but i don't know how to put the f(x) and g(x) into the equation.. I don't see those as options.. like i can type the like equation after the = sign but nothing before

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4you should have this typed in so far

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how did you get the f(x) there... just type?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok.. but no lines appear

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0If Gx=Fx, the 16t2+60t+82= 10+63.8t

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4your graph window may be off

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have a mac.. nothing is wrong with it.. so how is that possible?

Plasmataco
 one year ago
Best ResponseYou've already chosen the best response.0Des ps is a lot quicker :3

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4try setting the y min to 20 and the y max to 150

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4click the wrench on the right side to adjust the graph window

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4you should see something like this

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4now onto the table part select the box under the g(x). So select the third box then move up to the + button and add a table change the \(\Large x_1\) to just x. In the second column, replace \(\Large y_1\) with f(x). You'll see a list of numbers pop up in the third column, type g(x) at the top of this column. More numbers will pop up

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4the goal is to have the numbers be equal. Which row does this? Or do we get pretty close at all?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0they aren't appearing with numbers. i have the table and stuff.. but there aren't any numbers

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4you should see this

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4do you see any rows where f(x) = g(x) or pretty close to it?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4yep, so at about t = 2 seconds, the two objects will be at the same height (approximately)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0awesome! So is that part c??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay and Finally, Part D/

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4and it might be hard to see, but the projectile is falling down when they finally met up here is a zoomed in look dw:1439944300088:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.4if you click the intersection point between the two graphs, you'll see the point (2.006, 137.98) pop up. This is the more accurate approximate intersection point So at approx t = 2.006 seconds, the two objects are at an approx height of 137.98 ft

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 so if that is all.. I know your probably exhausted ...but could you help me with another problem I only need help on one part and its fairly simple???
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