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tw101
 one year ago
Write the equation of the parabola with a focus (1,2) and directrix y = 1.
tw101
 one year ago
Write the equation of the parabola with a focus (1,2) and directrix y = 1.

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tw101
 one year ago
Best ResponseYou've already chosen the best response.0Im not sure how to start.

tw101
 one year ago
Best ResponseYou've already chosen the best response.0okay the formula you put up above?

tw101
 one year ago
Best ResponseYou've already chosen the best response.0oh okay, onne second and then ill tell you what I got:)

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.2one may note that 1,2 is the focus point, not the vertex point

tw101
 one year ago
Best ResponseYou've already chosen the best response.0oh wait what does that mean then?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.2well... she maybe crazy, but still beautiful, so tis ok =)

tw101
 one year ago
Best ResponseYou've already chosen the best response.0im seriously confused though...

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.2dw:1439942544203:dw

tw101
 one year ago
Best ResponseYou've already chosen the best response.0Im not sure... Im sorry, this is new to me.

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.2hmmm well.. have you covered parabolas yet?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.2well.. it turns out that the focus point is "p" distance from the vertex and the directrix is "p" distance also from the vertex so.. the vertex is really halfway between both, since the focus and directrix are the same distance from the vertex keeping in mind that, the parabola opens up towards the focus point

tw101
 one year ago
Best ResponseYou've already chosen the best response.0Okay, well crazyandbeautiful helped me out and said that (1,3/2) was the vertex. haha.

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.2hmmm how did she get 1, 3/2 though?

tw101
 one year ago
Best ResponseYou've already chosen the best response.0haha no you dont need to its okay! @Crazyandbeautiful

tw101
 one year ago
Best ResponseYou've already chosen the best response.0okay so its always halfway between the focus point and directrix?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.2yeap, they're always "p" distance from the vertex

tw101
 one year ago
Best ResponseYou've already chosen the best response.0Where do I go from there?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.2so... get the vertex, get "p" and plug and chug \(\large{ \begin{array}{llll} (y{\color{blue}{ k}})^2=4{\color{purple}{ p}}(x{\color{brown}{ h}}) \\ (x{\color{brown}{ h}})^2=4{\color{purple}{ p}}(y{\color{blue}{ k}})\\ \end{array} \qquad \begin{array}{llll} vertex\ ({\color{brown}{ h}},{\color{blue}{ k}})\\ {\color{purple}{ p}}=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array}}\)
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