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anonymous

  • one year ago

Open Solution Problem;Soft snow can be compressed by pressure about 3.0 ×10^3 Pa. What is the smallest area that a pair of snowshoes must have if they will enable a 80 kg person to walk over the snow without sinking in? Consider g = 9.8 m/s2.

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  1. anonymous
    • one year ago
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    The first person who gets it earns a medal and fan

  2. anonymous
    • one year ago
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    First you have to consider the ?Newtonian force acting on the ground. This is caculated using Mg

  3. anonymous
    • one year ago
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    And use the equation Pressure=F/A(surface area in m^2) with inequality equation

  4. DDCamp
    • one year ago
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    First find the force the person will exert on the snow, using Newton's 2nd law: \[F = ma \\ F = 88kg * 9.8 \frac{m}{s^2}\]

  5. anonymous
    • one year ago
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    Correct! Newton's second law or simply mass*gravityt

  6. anonymous
    • one year ago
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    In fact you are calculating the normal force using that equation above

  7. DDCamp
    • one year ago
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    Use the equation for pressure:\[P = F/A \\ 3000 Pa = 862.4 N / A \\ A = 862.4N / 3000 Pa \\ A = 0.287 m^2\]

  8. anonymous
    • one year ago
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    Well done.

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