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## August899 one year ago Factor the polynomials:m^3+1/8 and p^3+216

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1. zepdrix

Hey :)

2. zepdrix

$\large\rm m^3+\frac{1}{8}$Hmmm, recall that we have a rule for factoring the sum of cubes: $\large\rm a^3+b^2=(a+b)(a^2-ab+b^2)$

3. zepdrix

But with the way our problem is written right now, we only have one cube. Any ideas how to turn the 1/8 into something^3 ?

4. zepdrix

@August899

5. August899

do we divide 1 over 8?

6. zepdrix

The 8 is some number to the third power.

7. zepdrix

Example: 27 is 3 to the third power. Because 3 x 3 x 3 = 27 Therefore $$\large\rm 27=3^3$$

8. zepdrix

Comeon Auguuuuuust >.< break down the 8, how can we write that another way?

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