anonymous
  • anonymous
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Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1439947712266:dw|
misty1212
  • misty1212
HI!!
misty1212
  • misty1212
this is pretty much impossible to read use the equation tool below and it will be clear

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misty1212
  • misty1212
i can try if you like
anonymous
  • anonymous
\[\left(\begin{matrix}9a ^{5}t ^{-1} \\ at ^{5}\end{matrix}\right)^{2}\]
misty1212
  • misty1212
\[\huge\left(\frac{9a^5t^{-1}}{at^5}\right)^2\]
anonymous
  • anonymous
yeah that's it.
misty1212
  • misty1212
lets work in side the parentheses first
misty1212
  • misty1212
\[\frac{a^5}{a}=a^4\] right?
misty1212
  • misty1212
and \[\frac{t^{-1}}{t^5}=\frac{1}{t^6}\] so we can go to \[\huge\left(\frac{9a^4}{t^6}\right)^2\]
misty1212
  • misty1212
then multiply all exponents by 2, don't forget to square the 9 as well
misty1212
  • misty1212
you got that last step?
anonymous
  • anonymous
okay to make sure I'm following correctly... would I get \[\frac{ 18a ^{8} }{ t ^{12} }\]
misty1212
  • misty1212
close, but you balked on squaring 9 you just doubled it
anonymous
  • anonymous
is everything right except for the 18?
misty1212
  • misty1212
yeah it should be \(81\)
misty1212
  • misty1212
since \(9^2=81\) unless maybe you have a fit of dyslexia, then it could be \(18\)
anonymous
  • anonymous
okay. Thanks for your help!
misty1212
  • misty1212
\[\color\magenta\heartsuit\]

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