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warpedkitten
 one year ago
The graph of f(x) consists of 14 points. Six of the points lie in Quadrant I of the coordinate plane. If f(x) is an odd function, what is the greatest number of points that can lie in Quadrant II?
warpedkitten
 one year ago
The graph of f(x) consists of 14 points. Six of the points lie in Quadrant I of the coordinate plane. If f(x) is an odd function, what is the greatest number of points that can lie in Quadrant II?

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Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.0hint: f(x) is odd, so #of points in Q1 = #of points in Q3

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.06 points in Q1 = 6 points in Q3 this gives us 6+6 = 12 points not in Q2 so if there are 14 points total, how many can be in Q2?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2if six are in quadrant 1, and it is odd, then 6 are in quadrant 3 right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2that leaves \(146=8\) to split between quadrant 2 and 4

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2if it is odd, however many you see in quadrant 2, you see in quadrant 4 so halve of the remaining 8

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2that is what i get, yes

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2say for example \((2,3)\) is a point in quadrant 2 on the graph then since \(f\) is odd, that means \((2,3)\) is also on the graph, and that is in quadrant 4
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