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sh3lsh
 one year ago
How do you factor cubics?
Such as x^3+5 x^2+7 x+3
or like
x^3+2 x^25 x6
Thanks,
sh3lsh
 one year ago
How do you factor cubics? Such as x^3+5 x^2+7 x+3 or like x^3+2 x^25 x6 Thanks,

This Question is Closed

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[x^3+5x^2+7x+3\] and you want to factor it?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1if you know one zero then you can factor it in general they do not factor using integer factors do you know a zero?

sh3lsh
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay, so I can guess and check to get the first zero. So, I guess and checked that 1 was a factor.

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1yes \(1\) is a zero, but as for the factor, if \(1\) is a zero then the factor is \((x+1)\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1that means \[x^3+5x^2+7x+3=(x+1)(\text{some quadratic})\] which you can find by a) long division (ick) b) synthetic division (very easy) or c) thinkin

sh3lsh
 one year ago
Best ResponseYou've already chosen the best response.0Oh yea! I don't want to make any mistake through c) so I'll pick b! I can look at a synthetic division algorithm online! Thanks so much!

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1if you want to make sure you get it right, just cheat

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=x%5E3%2B5x%5E2%2B7x%2B3

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[\color\magenta\heartsuit \]

sh3lsh
 one year ago
Best ResponseYou've already chosen the best response.0Haha! I've got to do this in linear with no calculator so unfortunately, I can't!

sh3lsh
 one year ago
Best ResponseYou've already chosen the best response.0I have a question in synthetic though,

sh3lsh
 one year ago
Best ResponseYou've already chosen the best response.0And I resolved it, you're the bomb. Thanks again!
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