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sh3lsh

  • one year ago

How do you factor cubics? Such as x^3+5 x^2+7 x+3 or like x^3+2 x^2-5 x-6 Thanks,

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  1. misty1212
    • one year ago
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    HI!!

  2. misty1212
    • one year ago
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    \[x^3+5x^2+7x+3\] and you want to factor it?

  3. sh3lsh
    • one year ago
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    Yeah!

  4. misty1212
    • one year ago
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    if you know one zero then you can factor it in general they do not factor using integer factors do you know a zero?

  5. sh3lsh
    • one year ago
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    Oh okay, so I can guess and check to get the first zero. So, I guess and checked that -1 was a factor.

  6. misty1212
    • one year ago
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    yes \(-1\) is a zero, but as for the factor, if \(-1\) is a zero then the factor is \((x+1)\)

  7. misty1212
    • one year ago
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    that means \[x^3+5x^2+7x+3=(x+1)(\text{some quadratic})\] which you can find by a) long division (ick) b) synthetic division (very easy) or c) thinkin

  8. sh3lsh
    • one year ago
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    Oh yea! I don't want to make any mistake through c) so I'll pick b! I can look at a synthetic division algorithm online! Thanks so much!

  9. misty1212
    • one year ago
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    if you want to make sure you get it right, just cheat

  10. misty1212
    • one year ago
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    http://www.wolframalpha.com/input/?i=x%5E3%2B5x%5E2%2B7x%2B3

  11. misty1212
    • one year ago
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    \[\color\magenta\heartsuit \]

  12. sh3lsh
    • one year ago
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    Haha! I've got to do this in linear with no calculator so unfortunately, I can't!

  13. sh3lsh
    • one year ago
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    I have a question in synthetic though,

  14. sh3lsh
    • one year ago
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    And I resolved it, you're the bomb. Thanks again!

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