How do you factor cubics? Such as x^3+5 x^2+7 x+3 or like x^3+2 x^2-5 x-6 Thanks,

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How do you factor cubics? Such as x^3+5 x^2+7 x+3 or like x^3+2 x^2-5 x-6 Thanks,

Mathematics
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HI!!
\[x^3+5x^2+7x+3\] and you want to factor it?
Yeah!

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if you know one zero then you can factor it in general they do not factor using integer factors do you know a zero?
Oh okay, so I can guess and check to get the first zero. So, I guess and checked that -1 was a factor.
yes \(-1\) is a zero, but as for the factor, if \(-1\) is a zero then the factor is \((x+1)\)
that means \[x^3+5x^2+7x+3=(x+1)(\text{some quadratic})\] which you can find by a) long division (ick) b) synthetic division (very easy) or c) thinkin
Oh yea! I don't want to make any mistake through c) so I'll pick b! I can look at a synthetic division algorithm online! Thanks so much!
if you want to make sure you get it right, just cheat
http://www.wolframalpha.com/input/?i=x%5E3%2B5x%5E2%2B7x%2B3
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Haha! I've got to do this in linear with no calculator so unfortunately, I can't!
I have a question in synthetic though,
And I resolved it, you're the bomb. Thanks again!

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