l2a+1l=1

- 0_0youscareme

l2a+1l=1

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- schrodinger

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- anonymous

that is better
this is an absolute value equation so it requires solving two separate equations

- anonymous

one is just what you see as if the absolute value signs are not there \[2a+1=1\] which you can solve in two easy steps

- anonymous

the other is what you get when you change the sign of the number on the right, i.e \[2a+1=-1\] again two easy steps to solve

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## More answers

- 0_0youscareme

so you pretend the absolute value sign is not there?

- anonymous

for one of them yes, but you have to solve two all together

- anonymous

so lets go ahead and solve them
start with \[2a+1=1\] and subtract 1 from both sides, what do you get?

- 0_0youscareme

you get 2a=0

- anonymous

right
which means \(a=?\)

- 0_0youscareme

0?

- anonymous

yes !
now on to the next equation

- anonymous

the next one is \[2a+1=-1\] again subtract 1, what do you get?

- 0_0youscareme

2a=-2

- anonymous

right, and now divide by 2

- 0_0youscareme

A=-1

- anonymous

yes
lets recap

- anonymous

if you have an absolute value equation like \[|2x+3|=5\] you have to solve two equations:\[2x+3=5\] and also \[2x+3=-5\]

- 0_0youscareme

so on a graph it would look like |dw:1439951388453:dw|

- anonymous

those two numbers, yes

- 0_0youscareme

okie tysm

- anonymous

btw the reason you were getting lots of confusion was because they thought you were asked to solve \[12a+11=1\]

- anonymous

yw

- 0_0youscareme

oh lol ic

- 0_0youscareme

can u help me with another question?

- anonymous

sure

- anonymous

as long as it is not statistics or geometry

- 0_0youscareme

yeah no its not

- 0_0youscareme

-3a+4=-14

- anonymous

no absolute values this time right?

- 0_0youscareme

no

- anonymous

a) subtract 4 from both sides
what do you get?

- 0_0youscareme

-3a=-18

- anonymous

ok good
now divide both sides by \(-3\)

- 0_0youscareme

a=6

- anonymous

bingo

- 0_0youscareme

omg tysfm ur so smart

- anonymous

lol you are quite welcome

- 0_0youscareme

i suck at math xD

- anonymous

actually you do not

- anonymous

most people have trouble at this level with the signed number arithmetic
you do not
if you are comfortable with that, you can do all these
btw you did them mostly yourself

- 0_0youscareme

can i ask u some more questions?

- anonymous

shoot

- 0_0youscareme

twelve is added to the product of a number and 5. the result is -3. find the number

- anonymous

ok here we need to translate in to math
product means multiply

- anonymous

so we pick a variable, or rather you pick one that will be "a number"

- 0_0youscareme

x

- anonymous

lol you have no imagination, i would have picked \(\xi\) but we will use \(x\)

- 0_0youscareme

xD

- anonymous

the "the product of a number and 5" will translate as \(5x\)

- 0_0youscareme

idky but ur making me want 2 actually learn

- anonymous

imagine!

- anonymous

now we add\(12\) to \(5x\) to get what?

- 0_0youscareme

5x+12? or 17x?

- anonymous

first one

- 0_0youscareme

okay

- anonymous

\[5x+12x=17x\] but \[5x+12=5x+12\]

- anonymous

now you are told that this give you \(-3\) so final job is to solve \[5x+12=-3\] takes two steps

- 0_0youscareme

subtract 12 witch gives u 5x=-15

- anonymous

yup
next?

- 0_0youscareme

then divide 5 and u get x=-3

- anonymous

ok i guess you are really not so "bad at math" after all

- 0_0youscareme

lool

- anonymous

at least not as bad as i was

- 0_0youscareme

u used 2 be bad at math?

- 0_0youscareme

im shocked

- anonymous

look, it is not like you are born knowing this
you have to practice is all

- 0_0youscareme

ic ic

- anonymous

you got more, or are you done?

- 0_0youscareme

i have a few more

- anonymous

go ahead and ask if you want, or try them and ask
btw who does homework in the middle of august?

- 0_0youscareme

its a summer packet

- anonymous

kk get you ready for fall

- 0_0youscareme

julie cashed a paycheck and repaid her brother $10 that she had borrowed from him. she then spent $30 on fuel for her car and half of the remaining money on a new tent for camping.she bought a pair of running shoes for $29.45 and had $17.75 left. how much did julie receive when she cashed her paycheck

- anonymous

wow

- 0_0youscareme

so much typing my fingers hurt

- anonymous

guess we need a variable again
guess we can recycle \(x\) as the amount of her original paycheck

- 0_0youscareme

i needa finsh this by 2day so my dad can unblock vantage smh

- anonymous

lolol!!!

- 0_0youscareme

fantage*

- 0_0youscareme

this is so laggy i have 2 keep refreshing

- anonymous

yeah i see that too

- anonymous

ok lets start with the amount cashed as \(x\) and start spending money

- anonymous

first spent $10 so has \(x-10\) left
then spend another 30 so what is left now?

- 0_0youscareme

x-40?

- anonymous

right
now here comes the confusing part

- anonymous

she spends half of that next, in other words half of \(x-40\) do you know what that is?

- 0_0youscareme

um 20?

- anonymous

you forgot to take half of \(x\)

- 0_0youscareme

so x-20?

- anonymous

you know, i have a much much better idea, lets approach this from a different way

- 0_0youscareme

okay

- anonymous

start at the end, and work backwards

- anonymous

- anonymous

at the end she had \(17.75\)
before that she spent \(29.45\) so how much did she have before spending the 29.45?

- anonymous

in other words, what is \(17.75+29.45\)?

- 0_0youscareme

47.20

- anonymous

yeah that is what i get

- anonymous

that is the "half the remaining money" so she had twice this amount before buying the stupid tent
how much is twice 47.20?

- 0_0youscareme

94,40

- 0_0youscareme

i mean 94.40

- anonymous

yeah right both times

- anonymous

now add the reaming two amounts she spent

- 0_0youscareme

134.40

- anonymous

looks reasonable

- anonymous

it is nice to do algebra without variables
in math it is called "arithmetic"

- 0_0youscareme

lol

- 0_0youscareme

i have 4 more questions do u still wanna help me with them?

- anonymous

sure

- anonymous

$15 per answer

- anonymous

$25 for correct ones

- anonymous

just kidding, go ahead lets see them

- 0_0youscareme

im poor asf

- 0_0youscareme

lmfao

- 0_0youscareme

okay

- 0_0youscareme

|dw:1439953689890:dw|

- anonymous

man is that ugly

- 0_0youscareme

lmfao fr

- 0_0youscareme

thats a 0 not a d js

- anonymous

add \(C\) to both sides, which really just means write it

- anonymous

\[\frac{A}{B}x=D+C\] in other words

- 0_0youscareme

oh ic ic

- anonymous

then multiply both side by the "reciprocal" of\(\frac{A}{B}\) which is \(\frac{B}{A}\) USE PARENTHESES !!

- anonymous

by which i mean put parentheses about the \(D+C\)

- 0_0youscareme

so \[\frac{ b }{ a } *\frac{ a }{ b }=(d+c)\frac{ b }{ }\]

- 0_0youscareme

\[\frac{ b }{ a }\] *

- anonymous

something like that

- anonymous

\[\huge x=\frac{b}{a}(c+d)\] looks somewhat more professional

- 0_0youscareme

lol okay ty

- anonymous

yw

- anonymous

3 more until fantage?

- 0_0youscareme

mhm

- 0_0youscareme

state whether the percent of change is a percent of increase or a percent of decrease. then find the percent of change. original:55 new:44

- anonymous

you tell me
is going from 55 to 44 an increase or a decrease?

- 0_0youscareme

decrease

- anonymous

ok so we got that out of the way
now lets compute the difference
what is \(55-44\)?

- 0_0youscareme

11

- anonymous

ok now compare to the original amount of 55 by division,i.e compute \[\frac{11}{55}\]

- 0_0youscareme

0.2?

- anonymous

right, and now turn it in to a percent by moving the decimal two place to the right

- 0_0youscareme

20% decrease

- 0_0youscareme

?

- anonymous

yes

- anonymous

two more

- 0_0youscareme

wow okay

- 0_0youscareme

a clown is preparing for a party by inflating one ballon for every invited guest. just when she has half of the necessary gallons inflated, 3 of them pop. she inflates 5 more balloons, and 2 go pop. then 6 balloons are carried away by the wind. she finishes by inflating 16 more balloons, and then learns that only 12 guest will attend the party. how many extra balling did the clown inflate

- anonymous

???

- 0_0youscareme

huh?

- anonymous

a clown is preparing for a party by inflating one ballon for every invited guest. just when she has half of the necessary gallons inflated, 3 of them pop
how many were originally invited?
btw i assume gallons means balloons

- 0_0youscareme

ballons not balling lmfao

- 0_0youscareme

and yea ballons

- 0_0youscareme

omg autocorrect

- 0_0youscareme

a clown is preparing for a party by inflating one balloon for every invited guest. just when she has half of the necessary balloons inflated, 3 of them pop. she inflates 5 more balloons, and 2 go pop. then 6 balloons are carried away by the wind. she finishes by inflating 16 more balloons, and then learns that only 12 guest will attend the party. how many extra balloons did the clown inflate

- 0_0youscareme

sorry for the misspelling

- anonymous

i think either there is not enough information or your answer has to have a variable in it

- anonymous

since we don't know how many guests were invited originally, we have no idea how many extra there are but we can write something i suppose

- anonymous

or we can assume that the number is 12 to begin with

- anonymous

lets say she starts with half of 12, which is 6 balloons

- anonymous

3 pop, how many left?

- 0_0youscareme

3

- anonymous

inflates 5 more
now how many?

- anonymous

??

- anonymous

report you? i don't even know you!

- anonymous

i dont report, i just ban
bye

- 0_0youscareme

8

- anonymous

ok now 2 pop
how many left?

- 0_0youscareme

6

- anonymous

now 6 get carried away
how many now?

- 0_0youscareme

nuffin

- anonymous

right

- anonymous

then inflates 16

- 0_0youscareme

i feel bad for the clown

- anonymous

which is 4 more than the 12 needed

- anonymous

not a good job i imagine

- 0_0youscareme

lol

- anonymous

brand new??!!

- 0_0youscareme

okay the last one has 2 do with geometry

- anonymous

not so good at that

- 0_0youscareme

okay ill do that one on with my brother he's good at math

- anonymous

ok good luck !!

- 0_0youscareme

okie tysfm for everything

- anonymous

you are quite welcome
see you again some time i am sure

- 0_0youscareme

lol yea buh byez

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