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Can someone please check question number 41 for me plz?!?!?!!?!?

can i suggest one thing

i don't care, spit it out!!!!

okay look

i am.....^_^

|dw:1439951841864:dw|

ive already done that....how do i figureout the horizontal displacement of the projectile.....??? :)

yes those are the initial vertical velocity and initial horizontal velocity.....

and to find how long its in Air for, we know the Vertival speed and we have the accerelation

one thing about the launch is that the starting and ending speed for the vertical is the same

jstu the direction is opposite

yup i know that.... :)

so what we need to do is see the time it takes for the velicity to go to 0 and mulitply by 2

comesout to 123.101

buddy that's not even closr to the real answer!!!

maybe some error somewhre xD

the answer is 40m.....

we're looking for the horizontal displacement of the ball....

here is the solution......wait

is it the initial horizontal velocity or the initial vertical velocity??????

dont use formulas just learn it

i think the answer there is wrong

it should be 123m ish

i wanna know what is the Vi2 means here????

vertical or horizontal......

what are u referring to again

hold up.....le me draw for you :)

wait i found the mistake they made

|dw:1439952832199:dw|

yes that is the right one

those are my numbers...when i plug them into their equation, i don't get the right answer????

did u get the method i was showing u up there?

i've tried both but i ain't getting 40m :"(

40 is wrong answer

yuss i already know that method.....

123 is right

you sure bra???

yes

i did it twice so it has to be right

well what do you get when you pplug in your findings into the formula, do you get 40?

let's try

i dont use formulas i dont know, id have to derive it

what formula do u want me to derive?

u want a formula with velocity and distance only?

:)

change in horzontal displacement = Vi^2 X Sin2 Theta/a

okay

|dw:1439953379986:dw|

okay that is fine

that is good

now look maybe u can help work this out

wait why is there a Vf=35 that doesnt eexist

Vertical
Vi=22.49m/s up
Vf=22.49m/s down

now tell me how much time that will take with 9.8m/s^2 acc

can u just answer this simpler qusetion first please

Vertical Vi=22.49m/s up Vf=22.49m/s down
how much time will this take? from this Vi to Vf?

remember acceleration =V/t right

so what is the time?

a = V/t yes!! :D

1 sec?

no

okay how much total change was there in the velocity

|dw:1439953983112:dw|

wait we have 2 velocities here Vi and Vf so which one am i going to use for that....??

|dw:1439953996826:dw|

accerelation = change in velocity / change in time

OMG i got it..... LOL

so how much did the time change by?

|dw:1439954092459:dw|

okay good

so this means it took 4.5 seconds for it go up and down

d= t/v

in this same time it was constantly moving horizontally at some speed

Horizontal speed * ~4.5 = distance in the horizontal
v*t=d

pellet...-_-

so 4.5s X 26.81m/s

yeah

121 LOL Yus!!! :"D

go online and look at a football being kicked in the air, see the approximate time

it just cannot be 40m meters that is too close

they will fire him if tahts the best he can kick it

this is an opening kick off

i was just following the steps....

i see i see i get it

There is only 2 real formulas u need to know for this whole course

dont worry, for all those u just need some geometry and these principles

try some more questions, post it on here if u are stuck

ok thanks ....:")

stay cute!!! :)

wait u got 50 something right

yah.....

what u got there is the change in vertical distance

nononoono

sorry different question.....

i'll post it if i have the energy....

okk get to work!

eye eye captain....:"D