anonymous
  • anonymous
you wanted a 1.8 M of KMNO4 and we know that the molecular weight of KMno4 is 158 g/mole how can we make the solution?
Chemistry
jamiebookeater
  • jamiebookeater
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taramgrant0543664
  • taramgrant0543664
v=m/c Where m is mass you can put that as 158g/mol possibly c is concentration so the 1.8M v is volume I don't know if this would work though sorry!
anonymous
  • anonymous
I will try to answer it the way you explained it, thanks a lot though!

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