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anonymous

  • one year ago

Justin Is Skeet Shooting During The Olympic Trails . The Height Of The Skeet is Modeled By The Equation : H: -5t^2 + 32t + 2 , Where H Is The Height iN Meters t Seconds After The Skeet Is Released . The Path Of Justins Bullet Is Modeled By The Equation : H=31.5t + 1 With The Same Units. How Long Does It Take For The Bullet To Hit The Skeet ? How High Off The Ground Will The Skeet Be When Its Been Hit? @jtvatsim

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  1. anonymous
    • one year ago
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    Hello There .

  2. anonymous
    • one year ago
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    Welcome Back :)

  3. jtvatsim
    • one year ago
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    Hey! Alright, so if you read the question slowly (not too fast or you'll freak yourself out), you should probably notice that this is very familiar to the other problem we did, so same steps as last time. :)

  4. anonymous
    • one year ago
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    Yes It Is Very Similar .

  5. jtvatsim
    • one year ago
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    1) Set equations equal (we want to see if the height of the skeet and bullet are ever the same) 2) Solve with quadratic formula. (Good ole, quadratics...)

  6. anonymous
    • one year ago
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    -5t^2 + 32t +2 =31.5t+1

  7. jtvatsim
    • one year ago
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    Very good! We are off to a great start with that.

  8. jtvatsim
    • one year ago
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    So, what's next? :)

  9. anonymous
    • one year ago
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    Then We Add And Subtract'

  10. jtvatsim
    • one year ago
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    Yes. In this case, both numbers are positive so we subtract them to get 0 (do the opposite). The details are like this: -5t^2 + 32t +2 =31.5t+1 -5t^2 + 32t +2 - 31.5t - 1 =31.5t+1 - 31.5t - 1 (subtracting from both sides to get 0) -5t^2 + 32t - 31.5t + 2 - 1 = 0 -5t^2 + 0.5t + 1 = 0

  11. anonymous
    • one year ago
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    Right

  12. jtvatsim
    • one year ago
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    Most people simplify this in their mind by just saying "do the opposite," but I am just showing what really happens. :)

  13. anonymous
    • one year ago
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    I Like The Way You Teach

  14. jtvatsim
    • one year ago
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    Thanks! Glad it's helping you! OK, so now you've got your equation set to 0, so our magic quadratic formula is allowed to come forth!

  15. jtvatsim
    • one year ago
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    This will take me a minute, I tend to be slow with this part... :)

  16. anonymous
    • one year ago
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    Us Both Lets Take Our Time

  17. jtvatsim
    • one year ago
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    OK, first one I'm seeing is t = -0.4... at least the decimals aren't quite as bad as last time.

  18. anonymous
    • one year ago
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    I Was Off A Little

  19. jtvatsim
    • one year ago
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    What did you get out of curiosity?

  20. anonymous
    • one year ago
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    -3.9

  21. anonymous
    • one year ago
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    I Used A Calculator

  22. jtvatsim
    • one year ago
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    Ah, I see! Probably just a calculator slip or parenthesis missing or something. Just for reference I'm using a = -5 b = 0.5 c = 1

  23. jtvatsim
    • one year ago
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    \[\frac{-0.5\pm \sqrt{0.5^2 - 4(-5)(1)}}{2(-5)}\]

  24. anonymous
    • one year ago
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    Your Right I Messed Up With Parenthesis

  25. jtvatsim
    • one year ago
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    Cool, at least you found the issue. Parenthesis always got me when I did these before. :P

  26. jtvatsim
    • one year ago
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    How about the other solution? Let me know what you get once you find it. Take your time. :)

  27. anonymous
    • one year ago
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    Ok

  28. anonymous
    • one year ago
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    X:-0.4

  29. anonymous
    • one year ago
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    x1=0.5

  30. jtvatsim
    • one year ago
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    Awesome, I got those two as well. :)

  31. jtvatsim
    • one year ago
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    Now, which one is the right one? Let's think and look at what the question is talking about again...

  32. jtvatsim
    • one year ago
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    It says, "How long does it take..." We could say "negative 0.4 seconds" which is kind of weird.... or "0.5 seconds" which makes a lot more sense. As another option, we could also check the equations with our answers like we did last time.

  33. anonymous
    • one year ago
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    Yes I Think That Would Be A Great idea To Check

  34. jtvatsim
    • one year ago
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    OK, well I just know you want to use the -5t^2 one, but restrain yourself and probably pick the simpler equation... :P

  35. jtvatsim
    • one year ago
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    Actually, you are even more on to the question than me. It does ask for the height after all, so checking the equations will tell us the height that we need. :)

  36. anonymous
    • one year ago
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    I Believe 0.5 Is The Correct 1

  37. jtvatsim
    • one year ago
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    I'm seeing: h = 31.5(-0.4) + 1 = -11.6 at t = -0.4 but, h = 31.5(0.5) + 1 = 16.75 at t = 0.5 Yes, I agree, the bullet being underground doesn't make sense (yet... until they invent new technology)

  38. jtvatsim
    • one year ago
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    Nice work! Getting the hang of it?

  39. anonymous
    • one year ago
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    Sort Of When Im Being Walked Through Makes Me Think ALOT More . Are You Up For More ?

  40. jtvatsim
    • one year ago
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    I know what you mean. It is less scary when you have a "guide" leading the way through the math jungle. :) Soon enough, you'll be able to think step by step on your own and help other people out too. Just takes practice. Sure let's take a look! I'll be waiting.

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