anonymous
  • anonymous
Justin Is Skeet Shooting During The Olympic Trails . The Height Of The Skeet is Modeled By The Equation : H: -5t^2 + 32t + 2 , Where H Is The Height iN Meters t Seconds After The Skeet Is Released . The Path Of Justins Bullet Is Modeled By The Equation : H=31.5t + 1 With The Same Units. How Long Does It Take For The Bullet To Hit The Skeet ? How High Off The Ground Will The Skeet Be When Its Been Hit? @jtvatsim
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Hello There .
anonymous
  • anonymous
Welcome Back :)
jtvatsim
  • jtvatsim
Hey! Alright, so if you read the question slowly (not too fast or you'll freak yourself out), you should probably notice that this is very familiar to the other problem we did, so same steps as last time. :)

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More answers

anonymous
  • anonymous
Yes It Is Very Similar .
jtvatsim
  • jtvatsim
1) Set equations equal (we want to see if the height of the skeet and bullet are ever the same) 2) Solve with quadratic formula. (Good ole, quadratics...)
anonymous
  • anonymous
-5t^2 + 32t +2 =31.5t+1
jtvatsim
  • jtvatsim
Very good! We are off to a great start with that.
jtvatsim
  • jtvatsim
So, what's next? :)
anonymous
  • anonymous
Then We Add And Subtract'
jtvatsim
  • jtvatsim
Yes. In this case, both numbers are positive so we subtract them to get 0 (do the opposite). The details are like this: -5t^2 + 32t +2 =31.5t+1 -5t^2 + 32t +2 - 31.5t - 1 =31.5t+1 - 31.5t - 1 (subtracting from both sides to get 0) -5t^2 + 32t - 31.5t + 2 - 1 = 0 -5t^2 + 0.5t + 1 = 0
anonymous
  • anonymous
Right
jtvatsim
  • jtvatsim
Most people simplify this in their mind by just saying "do the opposite," but I am just showing what really happens. :)
anonymous
  • anonymous
I Like The Way You Teach
jtvatsim
  • jtvatsim
Thanks! Glad it's helping you! OK, so now you've got your equation set to 0, so our magic quadratic formula is allowed to come forth!
jtvatsim
  • jtvatsim
This will take me a minute, I tend to be slow with this part... :)
anonymous
  • anonymous
Us Both Lets Take Our Time
jtvatsim
  • jtvatsim
OK, first one I'm seeing is t = -0.4... at least the decimals aren't quite as bad as last time.
anonymous
  • anonymous
I Was Off A Little
jtvatsim
  • jtvatsim
What did you get out of curiosity?
anonymous
  • anonymous
-3.9
anonymous
  • anonymous
I Used A Calculator
jtvatsim
  • jtvatsim
Ah, I see! Probably just a calculator slip or parenthesis missing or something. Just for reference I'm using a = -5 b = 0.5 c = 1
jtvatsim
  • jtvatsim
\[\frac{-0.5\pm \sqrt{0.5^2 - 4(-5)(1)}}{2(-5)}\]
anonymous
  • anonymous
Your Right I Messed Up With Parenthesis
jtvatsim
  • jtvatsim
Cool, at least you found the issue. Parenthesis always got me when I did these before. :P
jtvatsim
  • jtvatsim
How about the other solution? Let me know what you get once you find it. Take your time. :)
anonymous
  • anonymous
Ok
anonymous
  • anonymous
X:-0.4
anonymous
  • anonymous
x1=0.5
jtvatsim
  • jtvatsim
Awesome, I got those two as well. :)
jtvatsim
  • jtvatsim
Now, which one is the right one? Let's think and look at what the question is talking about again...
jtvatsim
  • jtvatsim
It says, "How long does it take..." We could say "negative 0.4 seconds" which is kind of weird.... or "0.5 seconds" which makes a lot more sense. As another option, we could also check the equations with our answers like we did last time.
anonymous
  • anonymous
Yes I Think That Would Be A Great idea To Check
jtvatsim
  • jtvatsim
OK, well I just know you want to use the -5t^2 one, but restrain yourself and probably pick the simpler equation... :P
jtvatsim
  • jtvatsim
Actually, you are even more on to the question than me. It does ask for the height after all, so checking the equations will tell us the height that we need. :)
anonymous
  • anonymous
I Believe 0.5 Is The Correct 1
jtvatsim
  • jtvatsim
I'm seeing: h = 31.5(-0.4) + 1 = -11.6 at t = -0.4 but, h = 31.5(0.5) + 1 = 16.75 at t = 0.5 Yes, I agree, the bullet being underground doesn't make sense (yet... until they invent new technology)
jtvatsim
  • jtvatsim
Nice work! Getting the hang of it?
anonymous
  • anonymous
Sort Of When Im Being Walked Through Makes Me Think ALOT More . Are You Up For More ?
jtvatsim
  • jtvatsim
I know what you mean. It is less scary when you have a "guide" leading the way through the math jungle. :) Soon enough, you'll be able to think step by step on your own and help other people out too. Just takes practice. Sure let's take a look! I'll be waiting.

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