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anonymous
 one year ago
Justin Is Skeet Shooting During The Olympic Trails . The Height Of The Skeet is Modeled By The Equation : H: 5t^2 + 32t + 2 , Where H Is The Height iN Meters t Seconds After The Skeet Is Released . The Path Of Justins Bullet Is Modeled By The Equation : H=31.5t + 1 With The Same Units. How Long Does It Take For The Bullet To Hit The Skeet ? How High Off The Ground Will The Skeet Be When Its Been Hit? @jtvatsim
anonymous
 one year ago
Justin Is Skeet Shooting During The Olympic Trails . The Height Of The Skeet is Modeled By The Equation : H: 5t^2 + 32t + 2 , Where H Is The Height iN Meters t Seconds After The Skeet Is Released . The Path Of Justins Bullet Is Modeled By The Equation : H=31.5t + 1 With The Same Units. How Long Does It Take For The Bullet To Hit The Skeet ? How High Off The Ground Will The Skeet Be When Its Been Hit? @jtvatsim

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jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0Hey! Alright, so if you read the question slowly (not too fast or you'll freak yourself out), you should probably notice that this is very familiar to the other problem we did, so same steps as last time. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes It Is Very Similar .

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.01) Set equations equal (we want to see if the height of the skeet and bullet are ever the same) 2) Solve with quadratic formula. (Good ole, quadratics...)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.05t^2 + 32t +2 =31.5t+1

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0Very good! We are off to a great start with that.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then We Add And Subtract'

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0Yes. In this case, both numbers are positive so we subtract them to get 0 (do the opposite). The details are like this: 5t^2 + 32t +2 =31.5t+1 5t^2 + 32t +2  31.5t  1 =31.5t+1  31.5t  1 (subtracting from both sides to get 0) 5t^2 + 32t  31.5t + 2  1 = 0 5t^2 + 0.5t + 1 = 0

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0Most people simplify this in their mind by just saying "do the opposite," but I am just showing what really happens. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I Like The Way You Teach

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0Thanks! Glad it's helping you! OK, so now you've got your equation set to 0, so our magic quadratic formula is allowed to come forth!

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0This will take me a minute, I tend to be slow with this part... :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Us Both Lets Take Our Time

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0OK, first one I'm seeing is t = 0.4... at least the decimals aren't quite as bad as last time.

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0What did you get out of curiosity?

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0Ah, I see! Probably just a calculator slip or parenthesis missing or something. Just for reference I'm using a = 5 b = 0.5 c = 1

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{0.5\pm \sqrt{0.5^2  4(5)(1)}}{2(5)}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Your Right I Messed Up With Parenthesis

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0Cool, at least you found the issue. Parenthesis always got me when I did these before. :P

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0How about the other solution? Let me know what you get once you find it. Take your time. :)

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0Awesome, I got those two as well. :)

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0Now, which one is the right one? Let's think and look at what the question is talking about again...

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0It says, "How long does it take..." We could say "negative 0.4 seconds" which is kind of weird.... or "0.5 seconds" which makes a lot more sense. As another option, we could also check the equations with our answers like we did last time.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes I Think That Would Be A Great idea To Check

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0OK, well I just know you want to use the 5t^2 one, but restrain yourself and probably pick the simpler equation... :P

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0Actually, you are even more on to the question than me. It does ask for the height after all, so checking the equations will tell us the height that we need. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I Believe 0.5 Is The Correct 1

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0I'm seeing: h = 31.5(0.4) + 1 = 11.6 at t = 0.4 but, h = 31.5(0.5) + 1 = 16.75 at t = 0.5 Yes, I agree, the bullet being underground doesn't make sense (yet... until they invent new technology)

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0Nice work! Getting the hang of it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sort Of When Im Being Walked Through Makes Me Think ALOT More . Are You Up For More ?

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.0I know what you mean. It is less scary when you have a "guide" leading the way through the math jungle. :) Soon enough, you'll be able to think step by step on your own and help other people out too. Just takes practice. Sure let's take a look! I'll be waiting.
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