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anonymous
 one year ago
Create your own exponential function, f(x), which models the snail population. You will need to identify the principal population of the snails and the rate of growth each year. Explain to Iris how your function shows the principal population and the rate of growth, in complete sentences.
anonymous
 one year ago
Create your own exponential function, f(x), which models the snail population. You will need to identify the principal population of the snails and the rate of growth each year. Explain to Iris how your function shows the principal population and the rate of growth, in complete sentences.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(x) = principal population (1 + growth rate as decimal)^x Pick a number for the principal population (aka initial amount) and pick a number for the growth rate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got this but im not sure if im right: f(x) = 2(5)^x , because i chose 2 to start off with, and the number of growth rate is 5...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or would i have to do it like this f(x) = 2(b)^5 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok that's great. So you started off with 2 snails and your growth rate is actually 400%. (5 = 1 + 4. The one is for the original amount, and the 4 is for the growth rate. 4 is the decimal form of 400%) f(x) = 2(5)^x is correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you help me with the other parts too please?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A local snail population grows according to the function g(x) = 200(1.03)2x. Demonstrate the steps to convert g(x) into an equivalent function with only x as the exponent. Then, explain to Iris how the key features of this local snail population compares to the key features of the invasive population.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can use this rule \[(x^m)^n=x^{mn}\] So \[200(1.03)^{2x}=200(1.03^2)^x\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then do 1.03² to find the growth rate for this one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Iris wants to graph the invasive snail population to show the city council. Justify what the appropriate domain and range would be for the function f(x), what the yintercept would be, and if the function is increasing or decreasing.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0y is the amount of snails and I assume x is time, so they both have to be greater than 0, and since the population is growing the function must be increasing. The yintercept will be the principal amount (population when x = 0)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0last one, In five years, a garden festival plans on using the park where Iris has been studying the invasive snails. Explain to the garden festival committee how to find the average rate of change for the snail population between years 2 and 5. Describe what this average rate of change represents.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0average rate of change is basically the slope between two point on the function. This is the formula between 2 and 5. \[aroc=\frac{ f(5)f(2) }{ 52}\] It would give the change in population over the 3 years.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you just saved my life! and can you make the 3d one a little more clear im struggling to solve the whole thing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0200(1.03)^2x=200(1.032)^x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you have to do 1.03^2 to get the number in parentheses Then subtract 1 to get the growth rate as a decimal

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so would it be f(x) = 200(1.0609)^x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and for the third one since it is growth in this situation, as the number heightens higher than it originally was, The range is [200, infinity) if the domain is [0, infinity) right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes. The domain is [0, inf). I suppose there's nothing wrong with making the range start at 200. I'd make is [0, inf) as well because population could technically drop below 200. But I think that's a personal choice.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank youuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
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