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anonymous

  • one year ago

The Height , H Of A Baksetball , in meters at t seconds after it is tossed out of a window is modeled by : H=-5t^2 + 20t +15. A Boy Shoots At The Baseball With A Paintball Gun . The Trajectory Of The Paintball Is Given By The Equation : H=3t + 3 . Will The Paintball Hit The Baseball ? IF So When? At What Height Will The Baseball bE ? @jtvatsim

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  1. jtvatsim
    • one year ago
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    Alrighty, what have we got here...

  2. jtvatsim
    • one year ago
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    "something is flying through the air, somebody does something to hit in midair" yep same problem type... :)

  3. anonymous
    • one year ago
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    Yup Sooo... -5t^2 +20t+15=3t +3

  4. jtvatsim
    • one year ago
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    Yessiree! Will the heights be equal? And when? Let's find out. The audience waits in suspense...

  5. anonymous
    • one year ago
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    Lets Fine Outt Next Step Add ?

  6. jtvatsim
    • one year ago
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    Either add or subtract, whatever will make the other side 0. Try something, and I'll let you know what I think. :)

  7. anonymous
    • one year ago
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    Ok Subtract Because there is only one negative .

  8. jtvatsim
    • one year ago
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    You are right to subtract. But not because there is only one negative. Let's pause on this step to make sure you've got this part down. That way, you'll always have the confidence to get through this stage. :)

  9. jtvatsim
    • one year ago
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    When I see -5t^2 + 20t + 15 = 3t + 3, I immediately focus my attention on the right side of the equation (look at 3t + 3).

  10. anonymous
    • one year ago
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    Ok

  11. jtvatsim
    • one year ago
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    Then, ask yourself, I see a 3t, how can I get rid of it? In this case I could just subtract a 3t from both sides like this: -5t^2 + 20t + 15 = 3t + 3 -3t -3t ___________________________ -5t^2 + 17t + 15 = 3 Then my 3t is gone!

  12. jtvatsim
    • one year ago
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    But, then, of course, I still see a pesky 3 there. How could I get rid of that since I just want zero on that side? Well... subtract a 3 from both sides, just like we did before! -5t^2 + 17t + 15 = 3 -3 -3 -------------------- -5t^2 + 17t + 12 = 0

  13. anonymous
    • one year ago
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    Ohhh i c

  14. jtvatsim
    • one year ago
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    Great! It's not too hard once you see the pattern. But it is a little hard to say in words. :)

  15. jtvatsim
    • one year ago
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    Here's one more example just to make sure you've got it. -66t^2 + 24t + 31 = -6t + 4 +6t +6t --------------------------- -66t^2 + 30t + 31 = 4 -4 -4 ---------------------- -66t^2 + 30t + 27 = 0

  16. jtvatsim
    • one year ago
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    In this case, I added to get rid of the -6t, but subtracted to get rid of the +4. Any questions on that process?

  17. jtvatsim
    • one year ago
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    And of course, what I just wrote above was a made-up example and has nothing to do with "our" current problem. :)

  18. anonymous
    • one year ago
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    i noticed Lol Those Off #;s

  19. jtvatsim
    • one year ago
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    Haha! I tried to make it obvious that I was going crazy there. ;) Anyways, we've got our equation now: -5t^2 + 17t + 12 = 0

  20. jtvatsim
    • one year ago
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    From what I've seen, that should be the end of the "hard" part mathematically. The rest of the problem is just making sure our calculator does the right thing. :)

  21. anonymous
    • one year ago
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    Yup Thats The Last Thing 2 do

  22. jtvatsim
    • one year ago
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    OK, then. Once you have your proposed solutions from the quadratic formula, we'll compare notes.

  23. anonymous
    • one year ago
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    Done

  24. jtvatsim
    • one year ago
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    Awesome! What did you get?

  25. anonymous
    • one year ago
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    x1=-0.5 x2 :4

  26. jtvatsim
    • one year ago
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    Yep, that's pretty close to what I got, x1 = -0.59999 x2 = 4

  27. anonymous
    • one year ago
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    i got the 9999 2 lol

  28. anonymous
    • one year ago
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    didnt think i needed it

  29. jtvatsim
    • one year ago
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    Oh, well, look at you! It's slightly different rounding -0.59 rounds to -0.6 (then I wouldn't have said anything...) You can feel that I'm becoming more nit picky! :) That's a good thing, it means you are moving beyond the basics. :)

  30. anonymous
    • one year ago
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    Lol Im Trying .. Another One Then Ill Leave You Alone Lol

  31. jtvatsim
    • one year ago
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    No worries! Glad to help. It's fun watching someone start out struggling, but then learn and start mastering it. It's really cool to see happen. :)

  32. jtvatsim
    • one year ago
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    So, we've got our possible solutions, but we need to check them. Here goes...

  33. jtvatsim
    • one year ago
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    Looks like t = -0.6 gives h = 1.2 and t = 4 gives h = 15

  34. anonymous
    • one year ago
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    The Correct One Is ....4

  35. jtvatsim
    • one year ago
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    I'd agree, even though the heights are both positive (and therefore possible), the negative time is weird. The answer is Yes, time is 4, and height is 15. Yahoo! :D

  36. anonymous
    • one year ago
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    Yay !!!!!!!!!! You Helped Me Sooo Much ..After This Next One Ill Have Just Four More ...Wouldve Been Up All Night

  37. jtvatsim
    • one year ago
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    You are welcome! Based on looking at the problems are they relatively similar? If not, I could help you look at one that is a different type if you feel comfortable with these "objects flying and hitting" questions.

  38. anonymous
    • one year ago
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    This Next One Is A Different One .

  39. anonymous
    • one year ago
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    Is a summer packet soo

  40. jtvatsim
    • one year ago
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    Let's take a look at it then if you want. Even if I have to log off soon, I can at least try to come up with a plan of attack. :)

  41. anonymous
    • one year ago
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    Sure

  42. jtvatsim
    • one year ago
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    sounds good

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