A community for students.
Here's the question you clicked on:
 0 viewing
YumYum247
 one year ago
A soccerball was kicked at an angle of 28 deg to the ground and it landed 39.8m away.
a) what was the velocity of the ball when kicked?
YumYum247
 one year ago
A soccerball was kicked at an angle of 28 deg to the ground and it landed 39.8m away. a) what was the velocity of the ball when kicked?

This Question is Closed

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1@Astrophysics just give me a quick hint and leave the rest to me.....

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1VECTORS PROJECTILE MOTION YAYAYAYA DIAGRAMS

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439958921010:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439959033896:dw I wanted to make an arc

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1just tell me what's the first thing i need to look for....that's all

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439959053044:dw now lets make it nice and clean so we know exactly what's going on, we need to find v0 here which is velocity of the ball when it was kicked.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You need to find your velocities at x and y direction, play around with it and apply kinematic formulas

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1yes but for that i need to find the final velocity :(

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439959268885:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1We don't actually need it, I have an idea!!!!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1Vertical: Horizontal: a = 9.8m/sec2 dh = 39.8m Dh = 0m/s Vh = ? Vi = ? t = ? Vf = ? t = ?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Ok I was actually thinking it gave us the maximum height

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1nope that's all we got???

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Good lets put everything in x and y direction...ok lets see and thing and have fun!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1sorry i forgot to add the theta in there... Vertical: Horizontal: a = 9.8m/sec2 dh = 39.8m Dh = 0m/s Vh = ? Vi = ? t = ? Vf = ? t = ? Angle = 28deg

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1x  direction x = 39.8 m \[\large v_{x_0} = v_0 \cos (28)\] ydirection a = g \[\large v_{y_0} = v_0 \sin(28)\] so this is what we're given hahahaaa

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Ok ok we can actually use the range formula

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1and find initial velocity instantly XD

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[R = \frac{ v_0^2\sin(2 \theta) }{ g }\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1hey about that..... what does it mean by Vi here, is it the horizontal velo or the vertical???

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Oh no that's the resultant velocity dw:1439960011427:dw what we're looking for

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1That can be split into components as shown to figure it out

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1yah cuz that formula says dh = Vi^2 X Sin2theta/a so that's why i was wondering what does that initial velocity means here....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1horizontal or vertical...cuz if it's the resultant then shouldn't it be Vf^2????

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I don't follow, that's the initial velocity, we are looking for the velocity that it was kicked at not at the velocity it landed at

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439960370291:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Oh I see what you're trying to do, no that's not right, because we're splitting the initial velocity into components

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439960455619:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Those are the components of the initial velocity, does that make sense?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1you can label it as i for initial it's the same thing :P

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1those nots confuse me ......i only understand Vf, Vi and Vh

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Ok sorry ill fix it

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439960585668:dw same thing

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1oh now i see...... :D

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yeah they are just components of the initial velocity :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[R = \frac{ v_i^2\sin(2 \theta) }{ g }\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1ok so where are we going with that formula, are we solving for the Vi there???

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1ok so it'll be like this....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439960730234:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1do we take the square root??? O_o

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Mhm hold on a sec, lets just do the algebra first to avoid confusion the range here is our x or distance which is 39.8 m. It's always best to do algebra first then plug things in especially when you get into deeper physics, it will benefit you. \[x= \frac{ v_i^2 \sin(2 \theta) }{ g }\] now solve for the initial velocity

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Don't plug anything in just solve for initial velocity

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1ok so rearrange the variables first....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1and then plug i nthe numbers....???

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1aight thanks man, i really appreciate your help..... Stay cute and blessed!!!! :")

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Np, lets just finish it off :P, so what do you get when you solve for initial velocity when you rearrange don't worry about making mistakes, that's how we learn!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1x = Vi^2 X Sin2theta/a x.a = Vi^2 X Sin2theta x.2/sin2Theta = Vi^2

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Perfect now just square root it and we're good!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439961336297:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I'm assuming that 2 in the numerator was meant to be an a haha

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1ok man thanks alot i really appreciate your effort.... stay blessed!! :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439961409567:dw whats that

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Hmm...our equation was \[x= \frac{ v_i^2 \sin(2 \theta) }{ g } \implies v_i = \sqrt{\frac{ gx }{ \sin(2 \theta) }}\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I think you may have added an extra x by mistake

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1yah!!! thats it....!!!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1no that's just my hand writing :"D

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1ok thanks and good night, sleep tight and don't let the bugs bite :"D
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.