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anonymous

  • one year ago

Hi, i ask this the other day and if someone can solve it with answer and explains, will fan and medal: When a beam makes an angle of 40 degrees with the ground, the top of the beam is 8 feet above the ground. There a telephone wires near by and the worker worried that the beam may hit the wires. When the beam makes a angle of 60 degrees with the ground, the wires are 2 feet above the beam. Will the beam hit the ground if the crew continues to raise it?

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  1. anonymous
    • one year ago
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    @radar

  2. anonymous
    • one year ago
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    I almost have the answers, i think?! call L is the hypotenuse of the figure: Sin 40 degree=8ft/L L=8ft/(Sin^ 40 )≈ 12.45 Call h is the lenght from thr beam to the ground at angle 60 degre: Sin 60=h/12.45 h=12.45(Sin 60) ≈ 10,78ft

  3. danica518
    • one year ago
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    |dw:1439959432329:dw|

  4. anonymous
    • one year ago
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    the teacher hints me that the beam WILL NOT hit the wires but I don't know how to prove it

  5. danica518
    • one year ago
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    okay so you see the height at 60 degrees is at 10.78 right

  6. danica518
    • one year ago
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    |dw:1439959659391:dw|

  7. anonymous
    • one year ago
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    yes

  8. danica518
    • one year ago
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    the wires at 2 feet about that so 10.78+2 = 12.78 feet and when the whole beam is put vertically that means the whole hypotenuse is on the vertical the height of the hypotenuse is 12.45 so it cant hit it

  9. danica518
    • one year ago
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    |dw:1439959743746:dw|

  10. danica518
    • one year ago
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    |dw:1439959797689:dw|

  11. danica518
    • one year ago
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    make sense?

  12. anonymous
    • one year ago
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    yes :) thank you, can you help me with 1 more? I'll post it after this :) please?

  13. danica518
    • one year ago
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    ok

  14. danica518
    • one year ago
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    sure

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