Hi, i ask this the other day and if someone can solve it with answer and explains, will fan and medal: When a beam makes an angle of 40 degrees with the ground, the top of the beam is 8 feet above the ground. There a telephone wires near by and the worker worried that the beam may hit the wires. When the beam makes a angle of 60 degrees with the ground, the wires are 2 feet above the beam. Will the beam hit the ground if the crew continues to raise it?

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Hi, i ask this the other day and if someone can solve it with answer and explains, will fan and medal: When a beam makes an angle of 40 degrees with the ground, the top of the beam is 8 feet above the ground. There a telephone wires near by and the worker worried that the beam may hit the wires. When the beam makes a angle of 60 degrees with the ground, the wires are 2 feet above the beam. Will the beam hit the ground if the crew continues to raise it?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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I almost have the answers, i think?! call L is the hypotenuse of the figure: Sin 40 degree=8ft/L L=8ft/(Sin^ 40 )≈ 12.45 Call h is the lenght from thr beam to the ground at angle 60 degre: Sin 60=h/12.45 h=12.45(Sin 60) ≈ 10,78ft
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the teacher hints me that the beam WILL NOT hit the wires but I don't know how to prove it
okay so you see the height at 60 degrees is at 10.78 right
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yes
the wires at 2 feet about that so 10.78+2 = 12.78 feet and when the whole beam is put vertically that means the whole hypotenuse is on the vertical the height of the hypotenuse is 12.45 so it cant hit it
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make sense?
yes :) thank you, can you help me with 1 more? I'll post it after this :) please?
ok
sure

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